【发布时间】:2018-07-12 07:46:11
【问题描述】:
我正在尝试从数据库表中获取 created_at 字段,但它抛出了以下错误:
无法将内部存储的日期/时间/时间戳值转换为 日期时间:'
Cook
' [wrapped: DateTime::__construct(): 失败 在位置 0 (Cook ):意外 特点]
获取日期代码:
foreach ($pager->getResults() as $row):
?>
<tr>
<td><?php echo $row->getTitle() ?></td>
<td><?php echo ($row->getStatus()) ? 'Active' : 'Inactive' ?></td>
<td><?php echo date(sfConfig::get('app_display_alternate_format_for_date'), strtotime($row->getCreatedAt())) ?></td>
<td>
</td>
</tr>
日期配置:
'app_display_alternate_format_for_date' => 'M-d-Y'
以 DB 格式保存日期:
2017-09-15 08:08:02
BaseModel 中的基本 getCreatedAt 函数:
public function getCreatedAt($format = 'Y-m-d H:i:s')
{
if ($this->created_at === null) {
return null;
}
if ($this->created_at === '0000-00-00 00:00:00') {
// while technically this is not a default value of NULL,
// this seems to be closest in meaning.
return null;
} else {
try {
$dt = new DateTime($this->created_at);
} catch (Exception $x) {
throw new PropelException("Internally stored date/time/timestamp value could not be converted to DateTime: " . var_export($this->created_at, true), $x);
}
}
if ($format === null) {
// Because propel.useDateTimeClass is TRUE, we return a DateTime object.
return $dt;
} elseif (strpos($format, '%') !== false) {
return strftime($format, $dt->format('U'));
} else {
return $dt->format($format);
}
}
【问题讨论】:
标签: php symfony date datetime symfony-1.2