在 sqlite 中查找两个时间戳之间的差异以获取下载时间

【问题标题】：Finding the differnce between two timestamps to get download time in sqlite在 sqlite 中查找两个时间戳之间的差异以获取下载时间
【发布时间】：2020-04-30 12:02:17
【问题描述】：

我正在尝试使用 python 解码 Chrome history.sqlite 文件：

我的Sql查询是：

SELECT 
  datetime(start_time/1000000-11644473600,'unixepoch','localtime') AS 'Decoded start_time (local time)', 
  datetime(end_time/1000000-11644473600,'unixepoch','localtime') AS 'Decoded end_time (local time)' 
FROM downloads

我的输出是（还有更多，但为简单起见，我只添加了一行）：

2020-04-11 18:55:54 2020-04-11 18:57:34

我想制作第三列，为我们提供两个时间戳之间的差异（以秒为单位）。

【问题讨论】：

标签： sqlite timestamp

【解决方案1】：

您可以像这样使用函数julianday()：

SELECT t.*,
  round((julianday(t."Decoded end_time (local time)") - julianday(t."Decoded start_time (local time)")) * 24 * 60 * 60, 0)
FROM (
  SELECT 
    datetime(start_time/1000000-11644473600,'unixepoch','localtime') AS "Decoded start_time (local time)", 
    datetime(end_time/1000000-11644473600,'unixepoch','localtime') AS "Decoded end_time (local time)" 
  FROM downloads
) t

或使用函数strftime():

SELECT t.*,
  strftime('%s', t."Decoded end_time (local time)") - strftime('%s', t."Decoded start_time (local time)")
FROM (
  SELECT 
    datetime(start_time/1000000-11644473600,'unixepoch','localtime') AS "Decoded start_time (local time)", 
    datetime(end_time/1000000-11644473600,'unixepoch','localtime') AS "Decoded end_time (local time)" 
  FROM downloads
) t

【讨论】：