'将列表喜欢传递给熊猫中的.loc

Question

我有以下日期列表：

date_list 
DatetimeIndex(['2015-07-10', '2015-07-13', '2015-07-14', '2015-07-15',
               '2015-07-16', '2015-07-17', '2015-08-20', '2015-09-21',
               '2015-09-22', '2015-09-23']

要访问这些日期的 pandas 中的行的值，我这样做了：

df['Close'].loc[dates_list]

这会产生以下错误：

KeyError: 'Passing list-likes to .loc or [] with any missing labels is no longer supported

如何获取这些DateTtimeindex 的行值

Answer 1

像魅力一样工作：

df.loc[date_list, 'Close']

测试示例，大致基于您提供的内容 - 如果与您的用例相比有什么不妥之处，请随时澄清细节：

import pandas as pd

date_list=pd.DatetimeIndex(['2015-07-10', '2015-07-13', '2015-07-14', '2015-07-15',
               '2015-07-16', '2015-07-17', '2015-08-20', '2015-09-21',
               '2015-09-22', '2015-09-23'])

df=pd.DataFrame({'Close': list("abcdefghijklmnoprstuvwxyz"), 'dt': ['2015-07-10', '2015-07-13', '2015-07-14', '2015-07-15','2017-01-01','2017-01-03','2015-07-01','2005-09-07', '2018-02-04',
               '2015-07-16', '2015-07-17', '2015-08-20', '2015-09-21','2019-04-06','2002-04-07','2002-05-19',
               '2015-09-22', '2015-09-23','2020-07-07', '2020-06-08', '2018-02-01', '2000-04-04', '2001-09-09', '2008-08-03', '2008-09-01']})
df['dt']=pd.to_datetime(df['dt'])
df=df.set_index('dt')
res=df.loc[date_list, 'Close']

>>> res

2015-07-10    a
2015-07-13    b
2015-07-14    c
2015-07-15    d
2015-07-16    j
2015-07-17    k
2015-08-20    l
2015-09-21    m
2015-09-22    r
2015-09-23    s
Name: Close, dtype: object