邮件功能错误答案

【问题标题】：Mailer function error邮件功能错误
【发布时间】：2015-06-05 10:42:08
【问题描述】：

SMTP -> 错误：服务器不接受数据：550 此邮件被归类为垃圾邮件，可能无法投递

$mail = new PHPMailer();
$mail->IsSMTP();
$mail->Host = "mail.cc.com";
$mail->SMTPAuth = true;
$mail->Username = "info@cc.com";
$mail->Password = "cc";
$mail->From = "cc.com"." <info@cc.com>"; 
$mail->AddReplyTo("cc1@gmail.com");
$mail->FromName = "info@cc.com";
$mail->AddAddress($climail);
$mail->AddCC("cc1@gmail.com");
$mail->Sender="info@cc.com";
$mail->IsHTML(true); 
$mail->WordWrap = 70;
$mail->Subject = $sub;
echo $meegate;
$mail->Body=$meegate;
$mail->SMTPDebug  = 1;
$mail->Send();

发送邮件时出错.. 邮件未发送..

【问题讨论】：

问题是？我建议你好好阅读how-to-ask
这是因为您使用的所有邮件 ID 都无效gmail ids。所以他们会在垃圾邮件文件夹中发送邮件。
添加了例如兄弟..

标签： php phpmailer

【解决方案1】：

您需要设置 SMTP 主机以及我猜的端口是 465：

$mail = new PHPMailer();
$mail->IsSMTP();
$mail->Host = "smtp.gmail.com";
$mail->SMTPAuth = true;
$mail->Username = "info@gmail.com";
$mail->Password = "cc";
$mail->From = "gmail.com"." <info@gmail.com>"; 
$mail->AddReplyTo("cc1@gmail.com");
$mail->FromName = "info@gmail.com";
$mail->AddAddress($climail);
$mail->AddCC("cc1@gmail.com");
$mail->Sender="info@gmail.com";
$mail->IsHTML(true); 
$mail->WordWrap = 70;
$mail->Subject = $sub;
echo $meegate;
$mail->Body=$meegate;
$mail->SMTPDebug  = 1;
$mail->Send();

【讨论】：

你为什么不用Php mail function？
Tr 使用这个：<?php $to = "abc@example.com,"; $subject = "HTML email"; $message = " <html> <body> <p>This email contains HTML Tags!</p> <table> <tr> <th>Firstname</th> <th>Lastname</th> </tr> <tr> <td>John</td> <td>Doe</td> </tr> </table> </body> </html> "; // Always set content-type when sending HTML email $headers = "MIME-Version: 1.0" . "\r\n"; $headers .= "Content-type:text/html;charset=UTF-8" . "\r\n"; // More headers $headers .= 'From: <a@example.com>' . "\r\n"; $headers .= 'Cc: b@example.com' . "\r\n"; mail($to,$subject,$message,$headers); ?>