如何使用 php 和 html 从 MySQL 数据库中显示表答案

【问题标题】：How to show table from MySQL database using php and html如何使用 php 和 html 从 MySQL 数据库中显示表
【发布时间】：2016-07-21 08:29:25
【问题描述】：

我正在尝试将我的 html 页面与 MySQL 数据库连接，以将来自一个特定表的数据显示到我的页面，但我总是得到一个错误，实际上它只是成为 SQL 代码的一部分。我对PHP编程真的很陌生，所以请有人帮助我，我做错了什么？这是我的代码：

<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>AJDE</title>
</head>
<?php
$servername = "localhost";
$username = "******";
$password = "*****";

// Create connection
$conn = new mysqli($servername, $username, $password);

// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

$query = "select * from PERCENTILE";
$result = mysqli_query($conn,$query);
if(!$result) {

    die ("Umro!");

    }
/* close connection */
$mysqli->close();
?>
<body>
</body>
</html>

谢谢！

【问题讨论】：

忘记选择数据库名称！！

标签： php mysql database

【解决方案1】：

您想将表格显示为 HTML 表格还是仅显示一个数组？

以下是我将表格显示为 HTML 表格的操作：

$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '*****';
$dbname = 'dbname';
$selectedTable = 'whateverTableYouWant';
$conn = mysqli_connect($dbhost, $dbuser, $dbpass,$dbname);
if (!$conn){
    die('cannot connect to mysql');
}

$query = "SELECT * FROM $selectedTable";
if ($result = mysqli_query($conn , $query)) {

    echo("<div class = 'data_wrapper'>");

    // Display Header of the table

    $fieldcount=mysqli_num_fields($result); //value = number of columns

    $row = mysqli_fetch_assoc($result);     //Fetch a result row as an associative array:

        //array to string conversion

        echo("<table id='example' class='table table-striped table-bordered' cellspacing='0' width='100%'>");

        echo("<thead> <tr>");

        foreach($row as $item){

            echo "<th>" .$item. "</th>";
        }

        echo("</tr> </thead>");


        //Footer
        echo("<tfoot> <tr>");

        foreach($row as $item){

            echo "<th>" .$item. "</th>";
        }

        echo("</tr> </tfoot>");



        //Display Data within the table
        echo("<tbody>");
        while ($row = mysqli_fetch_assoc($result)){
                echo "<tr>";
                foreach ($row as $item){
                    echo "<td contenteditable = 'true'>" . $item . "</td>"; //Change contenteditable later
                    //Editable data should be constricted, int = numbers only, string = words, date = date
            }
            echo "</tr>";
        }
        echo("<tbody>");
        echo "</table>";
        echo("</div>");

    }

以下只是显示为数组：

$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '*****';
$dbname = 'dbname';
$selectedTable = 'whateverTableYouWant';
$conn = mysqli_connect($dbhost, $dbuser, $dbpass,$dbname);

if (!$conn){
    die('cannot connect to mysql');
}
 $query = "SELECT * FROM $selectedTable";

 if ($result = mysqli_query($conn , $query)) {
    while ($row = mysqli_fetch_array($result)){
       print_r($row);
    }
 }

【讨论】：

非常感谢！你的回答对我帮助很大。
很高兴我能帮上忙！祝你的项目好运！ :D

【解决方案2】：

请按如下所述更改连接字符串。

<?php
$con = mysqli_connect("localhost","username","password","dbname");

// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }
?>

如果您有任何疑问，请告诉我。

【讨论】：

【解决方案3】：

我认为您需要选择一个用于运行查询的数据库：

试试这个代码：

<?php
$username = "your_name";
$password = "your_password";
$hostname = "localhost"; 

//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password) 
or die("Unable to connect to MySQL");
echo "Connected to MySQL<br>";

//select a database to work with (so replace the database name examples)
$selected = mysql_select_db("examples",$dbhandle) 
or die("Could not select examples");

//execute the SQL query and return records
$result = mysql_query("SELECT * FROM PERCENTILE");

//fetch the data from the database and display results
//replace id,name,year with the columns you have on your table PERCENTILE and you want to show
while ($row = mysql_fetch_array($result)) {
echo "ID:".$row{'id'}." Name:".$row{'name'}."Year: ". $row{'year'}."<br>";
}
//close the connection
mysql_close($dbhandle);
?>

希望对你有帮助，文斯。

【讨论】：