卷曲发布请求失败 - 脚本中的错误或被阻止？

Question

我正在尝试使用以下脚本向http://iate.europa.eu/ 发布请求：

     <?php

$output_array = array();

$post = "method=search&saveStats=true&screenSize=1920x1080&query=bond&valid=Szukaj+&sourceLanguage=en&targetLanguages=pl&domain=&domain=12&typeOfSearch=s&request=";

$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, 'http://iate.europa.eu/SearchByQueryEdit.do');
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/x-www-form-urlencoded'));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

echo $server_output = curl_exec ($ch);

?>

我使用的数据：

当我运行脚本时，我收到“拒绝访问。出于安全原因，您的请求已被拒绝。”

脚本会触发一些安全机制还是只是发出错误的请求？

提前谢谢，

卢卡斯

Answer 1

我已添加代理。试试这个：

$post = "method=search&saveStats=true&screenSize=1920x1080&query=bond&valid=Szukaj+&sourceLanguage=en&targetLanguages=pl&domain=&domain=12&typeOfSearch=s&request=";

$ch = curl_init();

/* Additional Code Start */
$agent = "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:30.0) Gecko/20100101 Firefox/30.0";        
curl_setopt($ch, CURLOPT_USERAGENT, $agent);
/* Additional Code End*/

curl_setopt($ch, CURLOPT_URL, 'http://iate.europa.eu/SearchByQueryEdit.do');
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/x-www-form-urlencoded'));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

echo $server_output = curl_exec ($ch);