【发布时间】:2017-10-31 13:40:54
【问题描述】:
给定以下标记:
<div class="viewport">
<iframe src="youtube.com/blabla"></iframe>
</div>
还有下面的css:
.viewport {
height: 100vh;
width: 100%;
}
iframe {
position: absolute;
}
并给出以下事实:
- 在 iframe 中播放的视频的宽高比为 16:9
是否可以编写一个脚本,将 iframe 拉伸到大于父级的大小,以便 iframe 溢出,隐藏黑条?(是的,我知道它也会裁剪部分视频,但没关系)
这是脚本必须解决的两个示例:
在第一张图片中,黑条位于左右两侧。为了解决这个问题,脚本会将 iframe 拉伸得更宽更高,从而将视频拉伸到里面,直到黑条消失。我们会丢失视频的顶部和底部,但没关系。在第二张图片中,黑条位于顶部和底部,我们需要将其拉伸并丢失视频的两侧。
这是我的注释尝试,但不幸的是,代码并未涵盖所有情况。一旦我的视口的纵横比高于~2.1,黑条就会回来。随意废弃我的脚本。
var block = $('.viewport');
var block_h = block.outerHeight();
var block_w = block.outerWidth();
var ratio = block_w / block_h;
// If viewport is landscape (black bars on left/right)
if( ratio >= 1.77777778 ) {
var video_w = (block_h * 16) / 9; // Get width of video within iframe
var total_black_bar_w = block_w - video_w; // Black bar total width
var new_iframe_w = (block_w + total_black_bar_w); // New width of the iframe needed to stretch the video wide enough to hide the black bars
var adjustment_percentage = new_iframe_w / block_w; // If we adjusted the width by 10% for example, then we also need to apply that percentage to the height
var new_iframe_h = (block_h * adjustment_percentage) + 30;
var pull_left = total_black_bar_w / 2; // how far to pull left to center the iframe outside of the parent container
var pull_top = (new_iframe_h - block_h) / 2; // same for top
}
// Portrait viewport (black bars on top/bottom)
else {
var video_h = (block_w * 9) / 16;
var total_black_bar_h = block_h - video_h;
var new_iframe_h = (block_h + total_black_bar_h);
var adjustment_percentage = new_iframe_h / block_h;
var new_iframe_w = (block_w * adjustment_percentage) + 30;
var pull_left = total_black_bar_w / 2;
var pull_top = (new_iframe_h - block_h) / 2;
}
block.find('iframe').css({
'width': new_iframe_w,
'height': new_iframe_h,
'left': '-' + pull_left + 'px',
'top': '-' + pull_top + 'px'
});
【问题讨论】:
标签: jquery html css video iframe