试图加入两个 MySQL 查询

Question

我希望这两个不同的表结果在一个查询中。

$result=mysqli_query("SELECT * FROM table_1 WHERE keyskill LIKE'php%'");
$result=mysqli_query("SELECT * FROM table_2 WHERE parentaddress LIKE'chennai%'");

谁能帮帮我？

这是表结构...

表 1：

  ID | F. Name | L.Name | Gender | Parentaddress  
___________________________________________________
 12  | Peter   | Son    |  Male  |  Chennai
 13  | Johny   | Depp   |  Male  |  Coimbatore

表 2：

 S.No|    Name | Title   | Gender | Keyskill  
 ___________________________________________________
 13  | Johny   | Student |  Male  |  PHP
 12  | Peter   | Student |  Male  |  JAVA

Answer 1

您的数据库不应该是这样的吗？ （只是猜测！）

表 1（人）：

  ID | F. Name | L.Name | Gender | Parentaddress  | Title  
__________________________________________________________
 12  | Peter   | Son    |  Male  |  Chennai       | Student
 13  | Johny   | Depp   |  Male  |  Coimbatore    | Student

表 2（技能）：

 S.No| ID | Keyskill  
 ___________________________________________________
 70  | 13 | PHP
 71  | 13 | Whatever Language
 72  | 12 | JAVA

表 1 定义了您要为其保存技能的人员，表 2 仅通过 iD 字段引用这些人员。

Answer 2

使用 UNION ：

select a.`ID` as ID, a.`F.Name` as first_name, a.`L.Name` as last_name, b.`Title` as tittle, a.`Gender` as gender, a.`Parentaddress` as parent_address, b.keyskill as keyskill from table_1 a inner join table_2 b on a.id = b.`S.No` where b.keyskill LIKE 'php%'
union all
select a.`S.No` as ID, b.`F.Name` as first_name, b.`L.Name` as last_name, a.`Title` as tittle, a.`Gender` as gender, b.`Parentaddress` as parent_address, a.`Keyskill` as keyskill from table_2 a inner join table_1 b where b.parentaddress LIKE 'chennai%'

或者通过 ID 加入：

select * from table_1 a left outer join table_2 b on a.id = b.`S.No` where b.keyskill LIKE 'php%' and a.parentaddress LIKE 'chennai%'