如何解决laravel中的“试图获取非对象的属性'pros_name'”？

Question

我的刀片中有以下 foreach 循环显示错误：

试图获取非对象的属性“pros_name”

我该如何解决？

@foreach ($reports as $report)
    <tr>
        <td>{{ $report->room_no }}</a></td>
        <td>{{ $report->room_type }}</td>
 @if($report->book_date== null || ($report->book_date != null && ($report->release_date != null && $report->release_date < date('Y-m-d'))))
        <td class="text-danger"><strong>Vacant</strong></td>
        <td>{{ $report->price }}</td>
                                <td>---</td>
                                <td></td>
                                @endif
                                @if($report->book_date != null && ( $report->release_date ==null || $report->release_date >= date('Y-m-d')))
                                    @php 
                                        $doc = DB::table('gen_resident_room')
                                            ->Join('sales_pipeline', 'gen_resident_room.person_id', '=', 'sales_pipeline.id')
                                            ->where([['room_id',$report->room_id]])->first();
                                            $n = explode (",",$doc->pros_name); //error
                                    @endphp
                                    @if($doc->stage === "MoveIn")
                                        <td class="text-success"><b>Occupied</b></td>
                                    @else
                                        <td class="text-success"><b>Booked</b></td>
                                    @endif
                                    <td>{{ $report->price }}</td>
                                    <td>{{ $doc->price }}</td>
                                    <td>{{ $n[0] }} {{ $n[1] }} {{ $n[2] }}</td>
                                @endif
                            </tr>
                            @endforeach

Answer 1

请尝试检查 $doc 是否包含数据。似乎文档是空的，所以它的脚本执行失败并抛出错误。

您也可以验证代码，例如：

if(!empty($doc))
{
 // Do you stuff
}

或

if(isset($doc->pros_name)) {
     $n = explode (",",$doc->pros_name);
}