PHP 联系表单空正文（引导程序）答案

【问题标题】：PHP Contact form empty body (bootstrap)PHP 联系表单空正文（引导程序）
【发布时间】：2015-12-18 02:54:51
【问题描述】：

我的联系表有问题（来自引导程序）。 php 代码以及 html 代码如下所示。每当我尝试联系表格时，正文都是空的。我错过了什么吗？这是html代码：

<form id="main-contact-form" class="contact-form" name="contact-form" method="post" action="sendemail.php">
              <div class="row-fluid">
                <div class="span5">
                    <label>First Name</label>
                    <input type="text" class="input-block-level" required="required" placeholder="Your First Name">
                    <label>Last Name</label>
                    <input type="text" class="input-block-level" required="required" placeholder="Your Last Name">
                    <label>Email Address</label>
                    <input type="text" class="input-block-level" required="required" placeholder="Your email address">
                </div>
                <div class="span7">
                    <label>Message</label>
                    <textarea name="message" id="message" required="required" class="input-block-level" rows="8"></textarea>
                </div>

            </div>
            <button type="submit" class="btn btn-primary btn-large pull-right">Send Message</button>
            <p> </p>

        </form>

这是 PHP 代码：

<?php
header('Content-type: application/json');
$status = array(
    'type'=>'success',
    'message'=>'Email sent!'
);

$name = @trim(stripslashes($_POST['name'])); 
$email = @trim(stripslashes($_POST['email'])); 
$subject = @trim(stripslashes($_POST['subject'])); 
$message = @trim(stripslashes($_POST['message'])); 

$email_from = $email;
$email_to = 'mail@luckystarmaids.com';

$body = 'Name: ' . $name . "\n\n" . 'Email: ' . $email . "\n\n" . 'Subject: ' . $subject . "\n\n" . 'Message: ' . $message;

$success = @mail($email_to, $subject, $body, 'From: <'.$email_from.'>');

echo json_encode($status);
die;

【问题讨论】：

标签： php html forms contact

【解决方案1】：

您的姓名和电子邮件表单元素没有name 属性。没有它们，它们将不会发布到表单的action^1、2。

将names 添加到您的输入中：

<input type="text" name="first_name" class="input-block-level" required="required" placeholder="Your Last Name">

此外，您还需要在 PHP 代码中处理名字和姓氏，此时您只需要查找 name。

【讨论】：

谢谢您，我已根据您的建议进行了编辑。但是，它仍然不起作用.. $email、$message 等仍然是空的。

【解决方案2】：

<form id="main-contact-form" class="contact-form" name="contact-form" method="post" action="">
  <div class="row-fluid">
        <div class="span5">
            <label>First Name</label>
            <input name=firstname type="text" class="input-block-level" required="required" placeholder="Your First Name">
            <label>Last Name</label>
            <input name=lastname type="text" class="input-block-level" required="required" placeholder="Your Last Name">
            <label>Email Address</label>
            <input name=email type="text" class="input-block-level" required="required" placeholder="Your email address">
            <label>Subject</label>
            <input name=subject type="text" class="input-block-level" required="required" placeholder="Subject">
        </div>
        <div class="span7">
            <label>Message</label>
            <textarea name="message" id="message" required="required" class="input-block-level" rows="8"></textarea>
        </div>

    </div>

    <button type="submit" class="btn btn-primary btn-large pull-right">Send Message</button>
    <p> </p>
</form>

也尝试处理服务器上的数据。至少检查值是否已发送：

        <?php

if ( isset( $_POST['firstname'] )
    && isset( $_POST['email'] )
    && isset( $_POST['subject'] ) 
    && isset( $_POST['message'] ) )
{


    $name = @trim(stripslashes($_POST['name'])); 
    $email = @trim(stripslashes($_POST['email'])); 
    $subject = @trim(stripslashes($_POST['subject'])); 
    $message = @trim(stripslashes($_POST['message'])); 

    $email_from = $email;
    $email_to = 'mail@luckystarmaids.com';

    $body = 'Name: ' . $name . "\n\n" . 'Email: ' . $email . "\n\n" . 'Subject: ' . $s

ubject . "\n\n" . 'Message: ' . $message;

$success = @mail($email_to, $subject, $body, 'From: <'.$email_from.'>');
if ($success)
{
        echo json_encode(array(
            'success'=> true,
            'message'=>'Email sent, you recieve an email at ' . $email
        ));
}    
}
else
{
    echo json_encode(array(
        'success' => false,
        'message' => 'An error has occured, please try again.'
    ));

}
?>

【讨论】：

对不起，我在一页中测试过。