Laravel Eloquent - 通过其他表连接 2 个表

Question

我通过第三个表在 2 个表之间建立关系。我总共有 3 张桌子。

1.) 地址

Schema::create('addresses', function (Blueprint $table) {
    $table->increments('id');
    $table->text('line_1_number_building')->nullable();
    $table->text('line_2_number_street')->nullable();
    $table->text('line_3_area_locality')->nullable();
    $table->text('city')->nullable();
    $table->text('zip_code')->nullable();
    $table->text('state_province_county')->nullable();
    $table->text('country')->nullable();
    $table->longText('other_address_details')->nullable();
    $table->timestamps();
});

2.) 员工

Schema::create('staffs', function (Blueprint $table) {
    $table->increments('id');
    $table->integer('staff_category_id');
    $table->integer('gender_id');
    $table->text('staff_job_title')->nullable();
    $table->text('staff_first_name')->nullable();
    $table->text('staff_middle_name')->nullable();
    $table->text('staff_last_name')->nullable();
    $table->text('staff_qualifications')->nullable();
    $table->date('staff_birth_date');
    $table->longText('other_staff_details')->nullable();
    $table->timestamps();
});

3.) 员工地址

Schema::create('staff_addresses', function (Blueprint $table) {
    $table->increments('id');
    $table->integer('staff_id');
    $table->integer('address_id');
    $table->date('date_address_from')->nullable();
    $table->date('date_address_to')->nullable();
    $table->timestamps();
});

现在我想获取任何员工条目的所有地址列表。我尝试了下面的代码，但它返回的地址与员工 ID 的 ID 匹配

我尝试了什么

public function saddresses()
{
    return $this->hasManyThrough('App\addresses','App\staff_addresses','staff_id','id');
}

我得到了什么

Address : [{"id":3,"line_1_number_building":"Hasan 2 line 1","line_2_number_street":"Hasan 2 line 2","line_3_area_locality":"Hasan 2 line 3","city":"Hasan 2 city","zip_code":"Hasan 2 zip code","state_province_county":"Hasan 2 state","country":"Hasan 2 country","other_address_details":"Hasan 2 other details","created_at":null,"updated_at":null,"staff_id":5},{"id":4,"line_1_number_building":"Sadiq 2 line 1","line_2_number_street":"Sadiq 2 line 2","line_3_area_locality":"Sadiq 2 line 3","city":"Sadiq 2 city","zip_code":"Sadiq 2 zip code","state_province_county":"Sadiq 2 state","country":"Sadiq 2 country","other_address_details":"Sadiq 2 other details","created_at":null,"updated_at":null,"staff_id":5}] 

Better view

你能指导我如何建立适当的关系吗？

问候， 哈桑·拉贾尼。

Answer 1

这个解决方案是完美的@Capt。提莫。但是，如果您想要特定员工的地址，那么我在这里提供了解决方案。

您必须在员工模型中定义此功能。

public function addresses() { return $this->belongsToMany('App\addresses'); }

查询获取$staffId的所有地址（其中$staffId是staff表的id）

$data = Staff::with('addresses')->where('id', $staffId)->first();

如果你想在数据透视表中获得额外的属性，你必须在定义关系时指定它们。

public function addresses() { return $this->belongsToMany('App\addresses')->withPivot('date_address_from', 'date_address_to'); }

另外，您可以在关系中使用withTimestamps 方法自动维护 created_at 和 updated_at 列。

供参考：https://laravel.com/docs/5.7/eloquent-relationships#many-to-many

Answer 2

首先，尝试修正您的命名约定。如果您遵循 laravel 的命名约定，事情会容易得多。 Here is the guide.

• 数据透视表应该是按字母顺序排列的单数模型名称（将 staff_addresses 更改为 address_staff）

然后使用belongsToMany 关系。

员工模特：

public function addresses()
{
    return $this->belongsToMany('App\addresses');
}

查询方式如下：

$data = Staff::with('addresses')->get();