【发布时间】:2016-01-22 05:35:04
【问题描述】:
问题
我在为 Parsley.js 插件创建自定义验证器时遇到问题。我想要做的是测试一个值与一个正则表达式。具体来说,我正在尝试验证密码值是否至少包含一个大写字母和一个小写字母。验证代码会引发错误,但在满足条件时不会返回 true。
HTML
<form name="Form" id="signupform" method="post" action="#" data-parsley-validate data-parsley-excluded="input[type=button], input[type=submit], input[type=reset], input[type=hidden], [disabled], :hidden">
<label for="password1">New Password <span class="req">*</span></label>
<input name="password" id="password1" type="password" class="password" data-parsley-minlength="1" data-parsley-errors-container=".errorspannewpassinput" data-parsley-required-message="Please enter your new password." data-parsley-mixedcase="^(?=.*[a-z])(?=.*[A-Z]).*$" data-parsley-required/>
<span class="errorspannewpassinput"></span>
<label for="confirm_password1">Confirm Password <span class="req">* </span></label>
<input name="Password_2" id="password2" type="password" class="password" data-parsley-minlength="1" data-parsley-errors-container=".errorspanconfirmnewpassinput" data-parsley-required-message="Please re-enter your new password." data-parsley-equalto="#password1" data-parsley-mixedcase="^(?=.*[a-z])(?=.*[A-Z]).*$" data-parsley-required />
<span class="errorspanconfirmnewpassinput"></span>
<input type="submit" name="submitinfo" id="submitsignup" data-theme="b" style="width:100%;" alt="Sign Up Now" value="Submit Account Request" />
</form>
jQuery
$(function() {
// Set variables
var pmixedCase = 'Y';
var mixedCase = $('.mixedcase');
var passwordField = $('#password1, #password2');
var passwordFieldErrors = $('.errorspannewpassinput, .errorspanconfirmnewpassinput');
// Assemble list of visible password requirements
// Mixed Case
if (pmixedCase === 'Y') {
mixedCase.show();
} else {
mixedCase.hide();
}
// Custom Validators
window.Parsley.addValidator('mixedcase', {
requirementType: 'regexp',
validateString: function(value, requirement) {
return requirement.test(value);
},
messages: {
en: 'Your password must contain at least (1) lowercase and (1) uppercase letter.'
}
});
});
我在下面包含了一个 JSFiddle。
【问题讨论】:
-
好吧,模式是
^(?=.*[a-z])(?=.*[A-Z]).*$,但它并不能解决整个问题:(。 -
我已经在上面的代码示例和小提琴中更新了这个。谢谢。我很确定 addvalidator 方法中存在问题。
标签: javascript jquery regex validation parsley.js