如何在 laravel 5.3 上使用 eloquent-relationships？答案

【问题标题】：How to use eloquent-relationships on laravel 5.3?如何在 laravel 5.3 上使用 eloquent-relationships？
【发布时间】：2017-01-13 17:30:05
【问题描述】：

我的控制器是这样的：

public function create()
{ 
    $data = array(
                'email' => 'chelsea@gmail.com'
            );

    $data = Order::where('email', $data['email'])->first();
    dd($data);
}

我的模型顺序是这样的：

<?php

namespace App\Models;

use Eloquent as Model;
use Illuminate\Database\Eloquent\SoftDeletes;
use Illuminate\Notifications\Notifiable;

class Order extends Model
{
    use SoftDeletes, Notifiable;

    public $table = 'orders';

    protected $dates = ['deleted_at'];

    public $fillable = [
        'number',
        'user_id',
        'store_id',
        'total_amount',
        'total_product',
        'service_amount',
        'status',
        'checkout_at'
    ];

    protected $casts = [
        'number' => 'string',
        'user_id' => 'integer',
        'store_id' => 'integer',
        'total_amount' => 'integer',
        'total_product' => 'integer',
        'service_amount' => 'integer',
        'status' => 'integer',
        'checkout_at' => 'date'
    ];

    public static $rules = [
        'user_id' => 'required',
        'store_id' => 'required'
    ];

    public function user()
    {
        return $this->belongsTo(User::class,'user_id','id');
    }

    public function store()
    {
        return $this->belongsTo(Store::class,'store_id','id');
    }
}

表用户有字段 id、姓名、电子邮件等

table store 有字段 id、name、email 等

我想从表用户和表存储中获取用户名和存储名。然后，我想将它存储在变量$data

我该怎么做？

更新

我的模型用户是这样的：

<?php

namespace App\Models;
use Eloquent as Model;
use Illuminate\Database\Eloquent\SoftDeletes;

class User extends Model
{
    use SoftDeletes;
    public $table = 'users';
    protected $dates = ['deleted_at'];

    public $fillable = [
        'name',
        'email',
        'password',
        'full_name',
        'birth_date',,
        'mobile_number',
    ];

    protected $casts = [
        'name' => 'string',
        'email' => 'string',
        'password' => 'string',
        'full_name' => 'string',
        'birth_date' => 'date',,
        'mobile_number' => 'string',
    ];

    public static $rules = [
        'name' => 'required',
        'email' => 'required'
    ];
}

我的模型店是这样的：

<?php

namespace App\Models;
use Eloquent as Model;
use Illuminate\Database\Eloquent\SoftDeletes;

class Store extends Model
{
    use SoftDeletes;
    public $table = 'stores';
    protected $dates = ['deleted_at'];

    public $fillable = [
        'user_id',
        'domain',
        'name',
        'email'
    ];

    protected $casts = [
        'user_id' => 'integer',
        'domain' => 'string',
        'name' => 'string',
        'email' => 'string'
    ];

    public static $rules = [
        'user_id' => 'required',
        'domain' => 'required',
        'name' => 'required'
    ];

    public function user()
    {
        return $this->belongsTo(User::class,'user_id','id');
    }
}

【问题讨论】：

@AddWeb Solution Pvt Ltd，我更新了我的问题
（离题）：不要让password 在你的用户模型中填写。我对此感到不安全 =)
@mosestoh：检查中...！
请先在Store模型和User模型中定义订单模型关系
我认为answer 可能会对您有所帮助。

标签： php laravel eloquent laravel-5.3

【解决方案1】：

首先你需要为用户表和存储表创建模型，然后在两个模型中定义各自的表名......

public function create(Request $request)
{ 
    $data  = $request->all();
    $email = 'chelsea@gmail.com';
    $user  = User::where('email', $email)->first();
    $store = Store::where('email', $user->email)->first();
    $order = Order::where('user_id', $user->id)->where('store_id', $store->id)->first();


    $result = array();
    $result['orderTable'] = $order;
    return $result;


}

【讨论】：

执行时：dd($result);，不存在商店名称和用户名。我需要它

【解决方案2】：

在您的订单控制器查询中使用with，只需传递您在订单模型查询中声明的关系数组，将根据模型关系获取相关表数据，如下所示

为了控制器

$data = Order::where('col', 'val')->with(['user','store'])->first();

按顺序模型

public function user()
{
    return $this->belongsTo(User::class,'user_id','id');
}

public function store()
{
    return $this->belongsTo(Store::class,'store_id','id');
}

【讨论】：