【问题标题】:org.json.JSONException: Value <br of type java.lang.String cannot be converted to JSONObject (Andriod Studio)org.json.JSONException:java.lang.String 类型的值 <br 无法转换为 JSONObject (Andriod Studio)
【发布时间】:2017-09-06 23:49:23
【问题描述】:

我正在尝试让一个在 Android Studio 中开发的 android 应用程序将数据从 注册用户活动 发送到数据库。这个想法是,一旦用户输入所有必需的信息并单击注册按钮,数据应该进入数据库,登录活动应该重新出现。但是,当我点击 Register user activity 上的注册按钮时,什么也没有发生,没有重定向到 Login activity 或数据被发送到数据库。

下面是我的注册用户活动代码:

package com.example.vi5h.split;
import android.content.Intent;
import android.support.v7.app.AlertDialog;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import com.android.volley.RequestQueue;
import com.android.volley.Response;
import com.android.volley.toolbox.Volley;
import org.json.JSONException;
import org.json.JSONObject;

public class RegisterUserActivity extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_register_user);

    final EditText etFullName = (EditText) findViewById(R.id.etFullName);
    final EditText etUsername = (EditText) findViewById(R.id.etUsername);
    final EditText etPassword = (EditText) findViewById(R.id.etPassword);
    final EditText etEmail = (EditText) findViewById(R.id.etEmail);
    final Button btnRegister = (Button) findViewById(R.id.btnRegister);

    btnRegister.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

            final String name = etFullName.getText().toString();
            final String username = etUsername.getText().toString();
            final String password = etPassword.getText().toString();
            final String email = etEmail.getText().toString();

            Response.Listener<String> responseListener = new Response.Listener<String>(){

                @Override
                public void onResponse(String response) {


                    try {
                        JSONObject jsonResponse = new JSONObject(response);
                        boolean success = jsonResponse.getBoolean("success");

                        if (success){
                            Intent intent = new Intent(RegisterUserActivity.this, LoginActivity.class);
                            RegisterUserActivity.this.startActivity(intent);

                        }else {
                            AlertDialog.Builder builder = new AlertDialog.Builder(RegisterUserActivity.this);
                            builder.setMessage("Register Failed")
                                    .setNegativeButton("Retry", null)
                                    .create()
                                    .show();
                        }


                    } catch (JSONException e) {
                        e.printStackTrace();
                    }


                }
            };


            RegisterRequest registerRequest = new RegisterRequest(name, username, email, password, responseListener);
            RequestQueue queue = Volley.newRequestQueue(RegisterUserActivity.this);
            queue.add(registerRequest);


        }
    });



}
}

下面是我的注册请求类代码:

package com.example.vi5h.split;
import com.android.volley.Response;
import com.android.volley.toolbox.StringRequest;
import java.util.HashMap;
import java.util.Map;


public class RegisterRequest extends StringRequest {

private static final String REGISTER_REQUEST_URL = "https://split.000webhostapp.com/Register.php";
private Map<String, String> params;

public RegisterRequest(String name, String username, String email, String password, Response.Listener<String> listener)
{

    super(Method.POST, REGISTER_REQUEST_URL, listener, null);
    params = new HashMap<>();
    params.put("name", name);
    params.put("username", username);
    params.put("email", email);
    params.put("password", password);
}


@Override
public Map<String, String> getParams() {
    return params;
}
}

下面是我的PHP脚本(Register.php):

<?php
$con = mysqli_connect("localhost", "id2833909_split421", "pass321", "id2833909_splitw");

$name = $_POST["name"];
$email = $_POST["email"];
$username = $_POST["username"];
$password = $_POST["password"];
$statement = mysqli_prepare($con, "INSERT INTO user (name, username, email, password) VALUES (?, ?, ?, ?)");
mysqli_stmt_bind_param($statement, "siss", $name, $username, $email, $password);
mysqli_stmt_execute($statement);

$response = array();
$response["success"] = true;  

echo json_encode($response);
?>

最后是我点击注册按钮后Logcat上抛出的错误: https://imgur.com/b8x0Su6

【问题讨论】:

  • 由于 &lt;br 开始一个 HTML 标签,你可能会得到一个错误页面。
  • @CommonsWare 嘿,谢谢你的回复,但你能说得更具体点吗.. 谢谢 :)

标签: java php android json database


【解决方案1】:

如果您在 Web 浏览器中访问 https://split.000webhostapp.com/Register.php,您会返回损坏的内容。它不是一个完整的网页,而是一堆错误信息:

<br />
<b>Notice</b>:  Undefined index: name in <b>/storage/ssd5/909/2833909/public_html/Register.php</b> on line <b>4</b><br />
<br />
<b>Notice</b>:  Undefined index: email in <b>/storage/ssd5/909/2833909/public_html/Register.php</b> on line <b>5</b><br />
<br />
<b>Notice</b>:  Undefined index: username in <b>/storage/ssd5/909/2833909/public_html/Register.php</b> on line <b>6</b><br />
<br />
<b>Notice</b>:  Undefined index: password in <b>/storage/ssd5/909/2833909/public_html/Register.php</b> on line <b>7</b><br />
<br />
<b>Warning</b>:  mysqli_stmt_bind_param() expects parameter 1 to be mysqli_stmt, boolean given in <b>/storage/ssd5/909/2833909/public_html/Register.php</b> on line <b>9</b><br />
<br />
<b>Warning</b>:  mysqli_stmt_execute() expects parameter 1 to be mysqli_stmt, boolean given in <b>/storage/ssd5/909/2833909/public_html/Register.php</b> on line <b>10</b><br />
{"success":true}

该响应的前三个字符是&lt;br。这些恰好是 JSON 解析器在您的错误消息中抱怨的前三个字符。所以,我的猜测是 Web 服务器正在发回相同类型的损坏内容以响应您的 Volley 请求。

所以,看看response,看看你得到了什么纯文本。然后,解决response 指示的任何问题。

【讨论】:

  • 嘿,谢谢,我会在早上尝试,您是否认为我的 PHP 脚本包含可能导致您访问链接时在 Web 浏览器上出现此响应的错误?
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