Symfony3 查询构建器 orderby 计数很少很多

Question

我有一个名为 Tag 的实体，它有 3 个 ManyToMany 关系节、文章和新闻。

AppBundle\Entity\Tag:
    type: entity
    table: tag
    ...
  manyToMany:
      news:
          orderBy: { 'posted': 'DESC' }
          targetEntity: News
          inversedBy: tags
          joinTable:
            name: news_tag
            joinColumns:
              tag_id:
                referencedColumnName: id
            inverseJoinColumns:
              news_id:
                referencedColumnName: id
      articles:
          orderBy: { 'posted': 'DESC' }
          targetEntity: Article
          inversedBy: tags
          joinTable:
            name: article_tag
            joinColumns:
              tag_id:
                referencedColumnName: id
            inverseJoinColumns:
              article_id:
                referencedColumnName: id
      fests:
          orderBy: { 'when_starts': 'DESC', 'when_ends': 'DESC' }
          targetEntity: Fest
          inversedBy: tags
          joinTable:
            name: fest_tag
            joinColumns:
              tag_id:
                referencedColumnName: id
            inverseJoinColumns:
              fest_id:
                referencedColumnName: id

现在我想编写一个 createQueryBuilder，它按计数“新闻”+ 计数“文章”+ 计数“节日”排序，仅用于查找“TOP TAGS”。我只为一个多对多关系找到了解决方案。

有什么办法吗？

编辑： 我有什么：

    $qb->select(array(
        't.id', 
        't.name', 
        'COUNT(f) as festcount',
        'COUNT(n) as newscount',
        'COUNT(a) as articlescount',
        '(COUNT(f) + COUNT(n) + COUNT(a)) as totalcount'
        ))
    ->from('AppBundle:Tag', 't')
    ->leftJoin('t.fests', 'f')
    ->leftJoin('t.articles', 'a')
    ->leftJoin('t.news', 'n')
    ->groupBy('t.id')
    ->orderBy('totalcount', 'DESC');

但它给出了虚假的结果。当某个标签有 3 个 fests、1 个文章和 0 个新闻时，结果是 festcount = 3，newscount = 0，articlescount = 3，totalcount = 6，应该是 4。

Answer 1

试试这个代码：

$qb->select(array(
        't.id', 
        't.name', 
        'COUNT(DISTINCT f.id) as festcount',
        'COUNT(DISTINCT n.id) as newscount',
        'COUNT(DISTINCT a.id) as articlescount',
        '(festcount + newscount + articlescount) as totalcount'
        ))
    ->from('AppBundle:Tag', 't')
    ->leftJoin('t.fests', 'f')
    ->leftJoin('t.articles', 'a')
    ->leftJoin('t.news', 'n')
    ->groupBy('t.id')
    ->orderBy('totalcount', 'DESC');

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