【发布时间】:2017-07-21 15:03:13
【问题描述】:
我正在加载一个简单的表单作为子视图,我需要将数据传递给下一个函数,但是当我使用$this->data时,我得到一个空白页。这是我的控制器:
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
class Search extends Admin_Controller {
function __construct()
{
parent::__construct();
$this->load->library('form_validation');
$this->load->helper('form');
$this->load->model('search_model');
}
function index()
{
$this->data['subview'] = ('../views/user/search_form');
$this->load->view('../views/_layout_admin', $this->data);
}
function execute_search()
{
// Retrieve the posted search term.
$search_term = $this->input->post('search');
// Use a model to retrieve the results.
$data['results'] = $this->search_model->get_results($search_term);
// Pass the results to the view.
$this->data['subview'] = ('../views/user/search_results');
$this->load->view('../views/user/search_results', $this->data);
}
}
任何帮助/想法?非常感谢
【问题讨论】:
-
嗨,我认为您需要阅读所有 codeigniter 的文档,因为当您在
application/views/...中加载视图时,您不需要仅使用$this->load->view('../views/---$this->load->view('views/...然后,当您发送 $data 查看你需要的是$this->load->view('../views/view_tamplate', $data);作为文档 -
你在用什么 $this->data 为什么不只用 $data?
标签: php forms codeigniter