将php对象值获取到数组中

Question

我希望将初始echo $zip 的输出作为简单的整数堆栈填充到数组中...我已经尝试过[]、{} 和各种其他访问器...再次感谢！

我有：

$userZip = new ZipCode($userZip);
$theZips = array();

foreach ($userZip->getZipsInRange(0, 10) as $miles => $zip) {

    echo $zip . '<BR>';

    $theZips = $zip;

}

print_r($theZips);

// print_r($theZips) output: 
ZipCode Object ( [zip_code_id:ZipCode:private] => 33816 [zip_code:ZipCode:private] => 21115 [lat:ZipCode:private] => 42.48 [lon:ZipCode:private] => -83.02 [city:ZipCode:private] => CENTER Ville [county:ZipCode:private] => [area_code:ZipCode:private] => [time_zone:ZipCode:private] => [state_prefix:ZipCode:private] => VA [state_name:ZipCode:private] => [mysql_table] => zip_code [mysql_conn] => [mysql_row:ZipCode:private] => Array ( [miles] => 8.88798662376604 [zip_code_id] => 33816 [zip_code] => 21119 [city] => City [state_prefix] => VA [lat] => 42.48 [lon] => -83.02 ) [print_name:ZipCode:private] => 48015 [location_type:ZipCode:private] => [miles] => 8.88798662376604 )   

// 已更新// 感谢尝试，但我得到了对象

print_R($theZips);

// 输出：

数组 ( [0] => 邮政编码对象 ( [zip_code_id:ZipCode:private] => 34026 [邮编：邮编：私人] => 21115 [纬度：邮政编码：私人] => 42.58 [lon:ZipCode:private] => -82.91 [city:ZipCode:private] => City Ville [县：邮编：私人] => [区域代码：邮政编码：私人] => [时区：邮编：私人] => [state_prefix:ZipCode:private] => VA [州名：邮编：私人] => [mysql_table] => 邮编 [mysql_conn] => [mysql_row:ZipCode:private] => 数组 ( [英里] => 0.000225049859756069 [zip_code_id] => 34026 [邮编] => 21115 [城市] => 城市小镇 [状态前缀] => VA [纬度] => 42.58 [lon] => -82.91 )

        [print_name:ZipCode:private] => 21119
        [location_type:ZipCode:private] => 
        [miles] => 0.000225049859756069
    ) 

Answer 1

foreach ($userZip->getZipsInRange(0, 10) as $miles => $zip) {

    echo $zip . '<BR>';    

    $theZips[] = $zip;  //push $zip into $theZips array    

}