【发布时间】:2017-09-09 12:26:26
【问题描述】:
我正在做一个项目,根据具体情况,我需要将一些输出数据组合成一个变量。
*$array 包含不同的用户信息
$array[]= array(
'ts3_uuid' => $value['client_unique_identifier'],
'channel_name' => $value['client_unique_identifier'],
'steam_id' => $steam_id,
'ts3_clid' => $value['clid'],
'channel_id' => $value['cid'],
'steam_name' => htmlspecialchars($steam_name),
'csgo_rank' => $csgo_rank,
'steam_status' => $steam_official_status,
'last_steam_connection' => $timestamp,
'steam_vac_status' => $result_steam_ban,
'csgo_played_time' => $total_tiempo_jugado,
'csgo_hs_porcentage' => $hs_porcent,
'csgo_kdr' => $kdr
);
foreach ($array as $data) {
$channel_description = $data['steam_name'];
}
这是我脑海中的结构......
if (the channel_id of different users are EQUAL){
combine their $data['steam_name'] into the $channel_description variable and
then, for example, echo it.
}
希望你能帮助我:-)
【问题讨论】:
-
那么,问题出在哪里?
-
试试这个数据 += newdata;
-
问题是我不知道如何将他们的数据“连接”到一个变量中,如果他们的 channel_id 是 EQUAL...
-
Rajendran Nadar 你能举个例子吗?