检查所有数组值是否存在于另一个数组值中[重复]

Question

我有一个要与另一个数组匹配的数组，第一个数组中的所有值都必须在第二个数组中，因此如果第二个数组长度小于第一个数组长度，它会自动变为 false。例如：

$products = array("soap","milk","book");
$availableProducts = array("soap","tea","oil","milk","book");
$this->matchArray($products,$availableProducts); //return true because  all $products value inside $availableProducts value too

$products = array("soap","milk","book");
$availableProducts = array("milk","tea","book","soap","oil");
$this->matchArray($products,$availableProducts); //return true because  all $products value inside $availableProducts value too

$products = array("soap","milk","book");
$availableProducts = array("soap","tea","oil","salt","paper");
$this->matchArray($products,$availableProducts); //return false because  only one of $products value inside $availableProducts value

$products = array("soap","milk","book");
$availableProducts = array("milk","book");
$this->matchArray($products,$availableProducts); //return false because  only two of $products value inside $availableProducts value 

Answer 1

您可以使用array_diff()

array_diff — 计算数组的差异

将 array1 与一个或多个其他数组进行比较并返回 array1 中的值不存在于任何其他数组中。

<?php

$products = array("soap","milk","book");
$availableProducts = array("soap","tea","oil","milk","book");

$difference = array_diff($products,$availableProducts);

if(count($difference)==0){

  echo "all products availabale";
}else{

  echo implode(',',$difference) ." are not available";
}

输出：-

1. https://eval.in/989587

2. https://eval.in/989588

3. https://eval.in/989593

4. https://eval.in/989596

Answer 2

PHP 提供了广泛的array functions。

您正在寻找array_diff()，根据文档：

将 array1 与一个或多个其他数组进行比较，并返回 array1 中不存在于任何其他数组中的值。