【发布时间】:2012-03-27 02:56:36
【问题描述】:
感谢@ManselUK 的回复
修复了这部分查找值(下)
但是,当我SELECT一个值时,它并没有设置隐藏元素的值,为什么不呢?
我收到错误:Uncaught TypeError: Cannot set property 'value' of null 当我从 autocomplete.. 中选择一个值时
输入5个字符调用的php代码:
try{
$occupation = mysql_real_escape_string($_GET['term2']); //////
echo 'term 2 '. $occupation;
///////////////////////////////////////////////////////////
///////////////////////////////////////////////////////////////////
$dbh->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
$sth = $dbh->prepare(
'SELECT occupID, occupVal From Occupation WHERE occupVal = ?');
$sth->bindParam(1, $occupation);
$sth->execute();
$jsonArray = array();
while ($result = $sth->fetch(PDO::FETCH_ASSOC)) {
$jsonArray[] = array(
'label' => $result['occupVal'],
'value' => $result['occupVal']."|".$result['occupID']);
}
print json_encode($jsonArray); // json encode that array
} // try
catch{} 代码块会将错误发送到文件,但该文件中没有错误。
HTML 表单输入:
<label for="occup">What is your occupation? <br /></label>
<div class="ui-widget">
<input id="occup" type="text" name="term2" value="e.g. Carpenter, Developer, etc" onFocus="clearText(this)" /><br />
<input type="hidden" id="actualOccup" name="actualOccupval" value="" />
输入内容时调用的JS:
<script type="text/javascript">
$(document).ready(function()
{
// Zipcode Field
$('input#zip').autocomplete({
dataType: "json",
source: "../src/php/registration/getFanLoc.php",
minLength: 4,
select: function(event, args){
event.preventDefault();
var joinedValues = args.item.value;
var id = joinedValues.split("|")[0];
var cityAndState= joinedValues.split("|")[1];
document.getElementById('actualZip').value = cityAndState ;
document.getElementById('zip').value = id;
}
});
// Occupation Field
$('input#occup').autocomplete({
source: function(request, response) {
$.getJSON("../src/php/registration/getFanOccupation.php", { term2: request.term }, response);
},
minLength: 5,
select: function(event, args){
event.preventDefault();
var joinedValues = args.item.value;
var id = joinedValues.split("|")[0];
var occupValAndId= joinedValues.split("|")[1];
$('#actualOccupval').val(occupValAndId);
$('#occup').val(id);
}
});
});
</script>
我尝试过调试:
- 检查此文件的错误日志。 (没有错误)
- 检查SELECT 查询,数据库中occupVal 的值是一个VARCHAR,在SQL 中通过执行occupVal = 'some val here'; 找到值jQuery 是否需要这些引号?
- 如果我直接访问getFanOccupation.php?term2=Computer Programmer,它会输出:term 2 Computer Programmer[{"label":"Computer Programmer","value":"Computer Programmer|183"}]
- 这是正确的,问题是如果我得到Computer Programmer值并直接粘贴到输入中,或者甚至开始写它,它
固定 JS: - 此代码有效,为职业选择了错误 ID,这就是它没有显示隐藏表单字段值的原因
$(document).ready(function()
{
// Zipcode Field
$('input#zip').autocomplete({
dataType: "json",
source: "file1.php",
minLength: 4,
select: function(event, args){
event.preventDefault();
var joinedValues = args.item.value;
var id = joinedValues.split("|")[0];
var cityAndState= joinedValues.split("|")[1];
document.getElementById('actualZip').value = cityAndState ;
document.getElementById('zip').value = id;
}
});
// Occupation Field
$('input#occup').autocomplete({
source: function(request, response) {
$.getJSON("file.php", { term2: request.term }, response);
},
minLength: 5,
select: function(event, args){
event.preventDefault();
var joinedValues = args.item.value;
var id = joinedValues.split("|")[0];
var occupValAndId= joinedValues.split("|")[1];
$('#actualOccup').val(occupValAndId);
$('#occup').val(id);
}
});
});
【问题讨论】:
标签: php jquery jquery-ui jquery-autocomplete