不使用ajax更新php中的数据库答案

【问题标题】：not update database in php with ajax不使用ajax更新php中的数据库
【发布时间】：2014-03-29 00:04:56
【问题描述】：

Index.php

<link href="css/validationEngine.jquery.css" rel="stylesheet" type="text/css" />

<script language="JavaScript" src="js/jquery-1.8.2.min.js" type="text/javascript"></script>

<script language="JavaScript" src="js/jquery.validationEngine-en.js" type="text/javascript"></script>

<script language="JavaScript" src="js/jquery.validationEngine.js" type="text/javascript"></script>

<script>
        jQuery(document).ready(function(){

            jQuery("#formID").validationEngine();

        });
</script>

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"></script>
<script type="text/javascript" src="js/jquery.form.js"></script>
<script type="text/javascript">
$(document).ready(function() 
{ 
    $('#photoimg').live('change', function()    
    { 
        $("#preview").html('');
        $("#preview").html('<img src="loader.gif" alt="Uploading1...."/>');

        $("#imageform").ajaxForm(
        {
        target: '#preview'
        }).submit();
    });
}); 
</script>
<style>
.preview { float: left;
    width: 57px;}

</style>

<link href="css/style.css" rel="stylesheet" type="text/css" />

<div class="form-container form-main-bg" style="margin-top:40px;">


<form id="imageform" name="imageform" method="post" enctype="multipart/form-data" action="ajax_upload_profile_image.php">
Upload image <input type="file" name="photoimg" id="photoimg" />
</form>

<div id='preview'>
</div>


    <form id="formID" name="formID" method="post" action="edit_profile.php">
        <input type="hidden" name="hid_id" id="hid_id" value="<?php echo $_SESSION['UserId']; ?>" />
            <div class="row">
            <div class="left">About</div>
            <div class="right">
            <textarea id="about" name="about" id="about"><?php echo $u_data[0]->vCode; ?></textarea>
            </div>
<div class="row">
            <div class="left">Location</div>
               <textarea id="location" name="location"><?php echo $u_data[0]->vCode; ?></textarea>            </div>

<div class="row">
            <div class="left">Gender</div>
            Male <input type="radio" name="gender" id="gender" value="male" />
            Female <input type="radio" name="gender" id="gender" value="female" />
            <div class="clear"></div>
            </div>

 <!- Other rows here -->
<div  style="text-align:center; margin-top:20px;">
<input name="submit" id="submit" type="submit" class="submit-btn" value="Update" />
</div>
</form>
</div>

ajax_upload_profile_image.php

<?php
    session_start();
    $session_id= $_SESSION['UserId'];

    require_once('includes/config.inc.php');
    if(isset($_POST) and $_SERVER['REQUEST_METHOD'] == "POST")
    {
        $path = "images/profile/";

        $valid_formats = array("jpg", "png", "gif", "bmp","jpeg");

        $name = $_FILES['photoimg']['name'];
        $size = $_FILES['photoimg']['size'];
        if(strlen($name))
        {
            list($txt, $ext) = explode(".", $name);
            if(in_array($ext,$valid_formats))
            {
                if($size<(1024*1024)) // Image size max 1 MB
                {
                    $actual_image_name = time().$session_id.".".$ext;
                    $tmp = $_FILES['photoimg']['tmp_name'];
                    if(move_uploaded_file($tmp, $path.$actual_image_name))
                    {
                        $query=("UPDATE users SET image='$actual_image_name' WHERE user_id='$session_id'");
                        $result = mysql_query($query) or die();
                        if($result)
                        {
                            echo "success"; 
                        }
                        else
                        {
                            echo "fail";
                        }

                        echo "<img src='images/profile/".$actual_image_name."' class='preview'>";
                    }
                    else
                        echo "failed";
                }
                else
                    echo "Image file size max 1 MB"; 
            }
            else
                echo "Invalid file format.."; 
        }
        else
            echo "Please select image..!";
        exit;
    }
?>

以下代码不起作用。使用表单操作将数据直接发送到 php 脚本时会更新数据库，但是通过 AJAX 函数将数据发送到 php 脚本时，数据库不会更新，但我会收到成功消息。

【问题讨论】：

标签： php jquery ajax

【解决方案1】：

.ajaxForm插件中的默认类型是GET。

在选项中添加type:"POST" 键。

【讨论】：

【解决方案2】：

尝试将session_start();移动到index.php

【讨论】：

我正在尝试但未修复