【发布时间】：2012-03-11 00:41:25
【问题描述】：
基本上我想要一个检索值 1 或 0 的表单来查看表单中是否存在电子邮件，并且我还想检索与电子邮件位于同一行的“用户名”列的名称。
这是 javascript/php 脚本（我从这里开始）： http://pastebin.com/zB0Umyyb
<!DOCTYPE html>
<html>
<head>
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>
<script>
$(document).ready(function() {
$("#tabs").tabs();
});
</script>
<script type="text/javascript">
$(document).ready(function() {
//the min chars for username
var min_chars = 3;
//result texts
var characters_error = 'Minimum amount of chars is 3';
var checking_html = 'Checking...';
//when button is clicked
$('#check_email_availability').click(function(){
//run the character number check
if($('#email').val().length < min_chars){
//if it's bellow the minimum show characters_error text
$('#email_availability_result').html(characters_error);
$(checking_html).hide();
}else{
//else show the cheking_text and run the function to check
$('#email_availability_result').html(checking_html);
check_availability();
$(checking_html).hide();
}
});
});
//function to check username availability
function check_availability(){
//get the username
var email = $('#email').val();
//use ajax to run the check
$.post("check_email.php", { email: email },
function(result){
//if the result is 1
if(result == 1){
//show that the username is available
$('#email_availability_result').html('<span class="is_available"><b>' +email + '</b> is Available</span>');
}else{
//show that the username is NOT available
$('#email_availability_result').html('<span class="is_not_available"><b>' +email + '</b> has already been refered</span>');
}
});
}
</script>
</head>
<body style="font-size:62.5%;">
<?
require ("config/config.php");
$result = mysql_query('select * from refer where email = "user@example.com" AND referred = "true"');
$row = mysql_fetch_array($result);
$usercheck = $row['username'];
?>
<div id="tabs">
<ul>
<li><a href="#fragment-1"><span>Refer</span></a></li>
<li><a href="#fragment-2"><span>Referal History</span></a></li>
<li><a href="#fragment-3"><span>Rewards</span></a></li>
</ul>
<div id="fragment-1">
<form>
<p>Minecraft User:
<input type='text' id='username'>
</p>
<p>Email Address:
<input type='text' id='email'> <input type='button' id='check_email_availability' value='Check Availability'>
</p>
</form>
<script>
$(document).ready(function() {
$("button").button();
});
</script>
<button> Refer! </button>
</br>
<div id='username_availability_result'></div>
</br>
<div id='email_availability_result'></div>
</div>
<div id="fragment-2">
<table border="1">
<tr>
<th>User</th>
<th>Referal Request</th>
</tr>
<tr>
<td>MrMan121</td>
<td>Pending</td>
</tr>
<tr>
<td>olimoli123</td>
<td>Accepted</td>
</tr>
</table>
</div>
<div id="fragment-3">
Rewards include:
dadadad.
</div>
</div>
</body>
</html>
这是它与之对话的 php 脚本： http://pastebin.com/tQppn84s
<?php
//connect to database
require ("config/config.php");
//get the username
$email = mysql_real_escape_string($_POST['email']);
//mysql query to select field username if it's equal to the username that we check '
$result = mysql_query('select email from refer where email = "'. $email .'" AND referred = "true"');
$row = mysql_fetch_array($result);
$usercheck = $row['username'];
//if number of rows fields is bigger them 0 that means it's NOT available '
if(mysql_num_rows($result)>0){
//and we send 0 to the ajax request
echo 0;
}else{
//else if it's not bigger then 0, then it's available '
//and we send 1 to the ajax request
echo 1;
}
?>
$usercheck 应该检查用户名。
【问题讨论】：
-
这是一个过于本地化的问题，因为它不会帮助任何人
-
Olivier，为了在未来获得支持，请确保您的帖子被表述为一个问题。这样一来，阅读的人就可以立即找出您遇到问题的方面。