【发布时间】:2017-06-09 06:16:22
【问题描述】:
Screenshot 我正在尝试验证一个复选框和多个文本框。文本框首先应该被禁用,并且只有在选中复选框时才应该启用。如果选中复选框的同一行上的文本框为空,则应弹出警报。
<table class="table table-bordered">
<tr align="center" style="background-color:black; color:white;">
<tr> <td colspan="8" style="background-color:silver;"><input type="submit" class="btn btn-primary" id="addSPtoCart" name="addSPtoCart" value="Add To Cart" class="button-L" /></td></tr>
<tr align="center" style="background-color:black; color:white;">
<td class="border"><span class="table-head"><label>Favorite</label></span></td>
<td><span class="table-head"><label>Material Code</label></span></td>
<td><span class="table-head"><label>Material Desc</label></span></td>
<td><span class="table-head"><label>Chart</label></span></td>
<td><span class="table-head"><label>Shade</label></span></td>
<td><span class="table-head"><label><?php echo $month1 ?></label></span></td>
<td><span class="table-head"><label><?php echo $month2 ?></label></span></td>
<td><span class="table-head"><label><?php echo $month3 ?></label></span></td>
<!--<td class="no-border" align="center"><span class="table-head">Action</span></td>-->
</tr>
<tr class="abc" align="center">
<style>.abc:nth-child(even){background-color: silver;}</style>
<td><input type="checkbox" name="fav[]" id="fav[]" value="<?php echo $d['materialID']; ?>" /></td>
<td><label><?php echo $d['materialCode']; ?></label></td>
<td><label><?php echo $d['materialDesc']; ?></label></td>
<td><label><?php echo $d['chart']; ?></label></td>
<td><label><?php echo $d['shade']; ?></label></td>
<td><input type="text" class="form-control" style="width:80px; " size ="5" name="qty_1<?php echo $d['materialID'] ?>" id="qty_1<?php echo $d['materialID'] ?>" value =<?php echo $var1 ?> ></td>
<td><input type="text" class="form-control" style="width:80px;" size ="5" name="qty_2<?php echo $d['materialID'] ?>" id="qty_2<?php echo $d['materialID'] ?>" value =<?php echo $var2 ?> ></td>
<td><input type="text" class="form-control" style="width:80px;" size ="5" name="qty_3<?php echo $d['materialID'] ?>" id="qty_3<?php echo $d['materialID'] ?>" value =<?php echo $var3 ?> ></td>
<!-- <td class="no-border" align="center"><a href="<?php //echo SITEURL; ?>/salesplan/salesplan-details/?id=<?php //echo $d['mmID']; ?>&mCatID=<?php// echo $_REQUEST["mCatID"];?> ">View</a></td> -->
</tr>
<tr><td colspan="8"><input type="submit" class="btn btn-primary" id="addSPtoCart" name="addSPtoCart" value="Add To Cart" class="button-L" /></td></tr>
</table>
<script type="text/javascript">
function validateForm() {
var x = document.forms["frmFav"]["qty_1"].value;
var y = document.forms["frmFav"]["qty_2"].value;
var z = document.forms["frmFav"]["qty_3"].value;
//var a = document.forms["frmFav"]["fav"].value;
if ((x == "") || (!this.frmFav.fav.checked)) {
alert("This field cannot be left empty !");
return false;
}
}
</script>
【问题讨论】:
-
你有没有尝试过?
-
提供你尝试过的 jsfiddle 链接?
-
@AbhaySinghania..refer this fiddle demo
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明确一点:您在问题中包含的验证代码是 JavaScript。您将需要在 PHP 中验证它以及在 JavaScript 中,因为用户可以绕过浏览器中的 JavaScript,因此您不能依赖正在完成的 JS 验证。
标签: javascript php twitter-bootstrap