【发布时间】:2015-05-11 09:50:47
【问题描述】:
如何将此 sql 转换为活动记录查询
SELECT * FROM `base_twitter` WHERE id NOT IN (SELECT base_id from base_followers)
【问题讨论】:
如何将此 sql 转换为活动记录查询
SELECT * FROM `base_twitter` WHERE id NOT IN (SELECT base_id from base_followers)
【问题讨论】:
假设您的模型相应地命名为 BaseTwitter 和 BaseFollower,这应该可以工作:
$subQuery = BaseFollower::find()->select('id');
$query = BaseTwitter::find()->where(['not in', 'id', $subQuery]);
$models = $query->all();
【讨论】:
// SELECT * FROM (SELECT * FROM `user` WHERE `active` = 1) `activeusers`;
$subquery = (new \yii\db\Query)->from('user')->where(['active' => true])
$query = (new \yii\db\Query)->from(['activeusers' => $subquery]);
// subquery can also be a string with plain SQL wrapped in parenthesis
// SELECT * FROM (SELECT * FROM `user` WHERE `active` = 1) `activeusers`;
$subquery = "(SELECT * FROM `user` WHERE `active` = 1)";
$query = (new \yii\db\Query)->from(['activeusers' => $subquery]);
【讨论】:
试试这个查询
$models = BaseTwitter::find()->where('id NOT IN (SELECT base_id from base_followers)')->all();
【讨论】: