Codeigniter 检查 index.php 文件中是否有 LoggedIn

Question

我真的需要帮助，我在 2 天前自己寻求解决方案，但没有结果。 我需要检查用户是否登录使用：

$CI =& get_instance(); $loggedIn = $CI->session->userdata('loggedin') == TRUE

如果 $loggedIn 为 true，则表示用户已登录。我需要在索引文件中检查这个，因为我从中选择了数据库：

$parsed = parse_url($_SERVER['REQUEST_URI']);
$path = $parsed['path'];
$path_parts = explode('/', $path);
$db = $path_parts[4]; 


if(isset($db) && is_numeric($db)){
    define('DB', $db);
}

$db 是我的数据库的名称，所以如果我在登录页面中，则没有问题，因为它是在 url 中设置和数字的。但是当我登录时，我将此 $db 存储在会话变量中，因此我需要进行此测试：

if($this->session->userdata('loggedin') == TRUE){
    define('DB', $this->session->userdata('db'));
}

我的数据库文件：

   $active_group = 'default';
   $active_record = TRUE;
   $db['default']['hostname'] = 'localhost';
   $db['default']['username'] = '*********';
   $db['default']['password'] = '*********';
   $db['default']['database'] = DB;
   $db['default']['dbdriver'] = 'mysql';
   $db['default']['dbprefix'] = '';
   $db['default']['pconnect'] = FALSE;
   $db['default']['db_debug'] = TRUE;
   $db['default']['cache_on'] = FALSE;
   $db['default']['cachedir'] = '';
   $db['default']['char_set'] = 'utf8';
   $db['default']['dbcollat'] = 'utf8_general_ci';
   $db['default']['swap_pre'] = '';
   $db['default']['autoinit'] = TRUE;
   $db['default']['stricton'] = TRUE;

平均问题是我需要通过 url 使用不同的数据库。如果用户输入此链接，例如：/user/login/34，他将使用名为 34 的数据库。

我正在使用 codeigniter php 框架 core/MY_Controller.php的代码

class MY_Controller extends CI_Controller
{
    public $data = array();
    function __construct ()
    {
        parent::__construct();

        $this->data['errors'] = array();
        $this->data['app_name'] = config_item('app_name');
        $this->load->helper('form');
        $this->load->library('form_validation');
        $this->load->model('user_m');

        $db_prefix = 'autojahi_dev';
        $config = array(
           'hostname' => 'localhost',
           'username' => '****',
           'password' => '****',
           'database' => '****',
           'dbdriver' => 'mysql',
           'dbprefix' => '',
           'pconnect' => FALSE,
           'db_debug' => TRUE,
           'cache_on' => FALSE,
           'cachedir' => 'cache',
           'char_set' => 'utf8',
           'dbcollat' => 'utf8_general_ci',
           'swap_pre' => '',
           'autoinit' => TRUE,
           'stricton' => TRUE
        );

        if($this->uri->segment(4)){
               $config['database'] = $this->uri->segment(4);
        }          

      $this->load->database($config);
      //$this->db->reconnect();//shouldnt be required but try it if there is problem
      echo $this->db->database;//for testing 


        $current_link = uri_string();

        // Algorithm of autojahiz access autorization

        $allow_not_loggedin = array('login', 'logout', 'reset_pass', 'send_reset_pass_email', 'reset_pass_form', 'update_pass', 'views', 'invalid_link' );

        switch (strtolower( $this->router->class ) )
        {
            case 'user':
                $allow_loggedin = array('denied', 'index', 'edit', 'logout');
            break;

            case 'dashboard':
                $allow_loggedin = array('denied', 'index');
            break;
        }

        if ( $this->session->userdata('loggedin') == FALSE ) 
        {   
            if (!in_array( $this->router->method, $allow_not_loggedin) )
            {
                redirect( 'user/login' );
            }
        }
        else
        {   
            if (!in_array( $this->router->method, $allow_loggedin ) )
            {
                //redirect( 'user/denied' );
            }
        }
    }
}

Answer 1

在您的控制器中执行此操作。为方便起见，您可以在 application/core 文件夹中创建一个名为 MY_Controller.php 的扩展文件，并扩展到您的控制器，如

class Other_controller extends MY_Controller{}

在 application/core/MY_Controller.php 构造函数中做..

class MY_controller extends CI_Controller{

  public function __construct() {

   parent::__construct();

   $config = [
   'hostname' => '',
   'username' => '',
   'password' => '',
   'database' => 'defaultdb',
   'dbdriver' => 'sqlsrv',
   'dbprefix' => '',
   'pconnect' => TRUE,
   'db_debug' => TRUE,
   'cache_on' => FALSE,
   'cachedir' => APPPATH .'cache',
   'char_set' => 'utf8',
   'dbcollat' => 'utf8_general_ci',
   'swap_pre' => '',
   'autoinit' => TRUE,
   'stricton' => FALSE
  ];

  if($this->uri->segment(4)){
       $config['database']=$this->uri->segment(4);
  }          

  $this->load->database($config);

  $this->db->reconnect();//shouldnt be required but try it if there is problem

  echo $this->db->database;//for testing 

}

Answer 2

不确定这是否正是您所需要的，但我会这样做：

在 application/core 中，创建 MY_Loader.php

class MY_Loader extends CI_Loader
{

    public function database($params = '', $return = FALSE, $query_builder = NULL)
    {
        // Grab the super object
        $CI =& get_instance();
        $CI->load->library('session');

        $db_name = "mydefault_db";
        if($CI->session->userdata('db'))
            $db_name = $CI->session->userdata('db');

        $params['hostname'] = "localhost";
        $params['username'] = "root";
        $params['password'] = "";
        $params['database'] = $db_name;
        $params['dbdriver'] = "mysqli";
        $params['dbprefix'] = "";
        $params['pconnect'] = FALSE;
        $params['db_debug'] = TRUE;
        $params['cache_on'] = FALSE;
        $params['cachedir'] = "";
        $params['char_set'] = "utf8";
        $params['dbcollat'] = "utf8_general_ci";

        // Do we even need to load the database class?
        if ($return === FALSE && $query_builder === NULL && isset($CI->db) && is_object($CI->db) && ! empty($CI->db->conn_id))
        {
            return FALSE;
        }

        require_once(BASEPATH.'database/DB.php');
        if ($return === TRUE)
        {
            return DB($params, $query_builder);
        }

        // Initialize the db variable. Needed to prevent
        // reference errors with some configurations
        $CI->db = '';

        // Load the DB class
        $CI->db =& DB($params, $query_builder);
        return $this;
    }
}

然后在控制器中：

public function login($db_id)
{
    $this->session->set_userdata('db', $db_id);

    //Your stuff here

    //let's suppose we have a flag for the login success
    if(!$logedin)
        $this->session->unset_userdata('db');
}

Answer 3

如果我是你，我将定义所有将使用的数据库，如下所示：

$db[30] = array(
    'hostname' => '',
    'username' => '',
    'password' => '',
    'database' => '',
    'dbdriver' => 'sqlsrv',
    'dbprefix' => '',
    'pconnect' => TRUE,
    'db_debug' => TRUE,
    'cache_on' => FALSE,
    'cachedir' => APPPATH .'cache',
    'char_set' => 'utf8',
    'dbcollat' => 'utf8_general_ci',
    'swap_pre' => '',
    'autoinit' => TRUE,
    'stricton' => FALSE
);

$db[32] = array(
    'hostname' => '',
    'username' => '',
    'password' => '',
    'database' => '',
    'dbdriver' => 'pdo',
    'dbprefix' => '',
    'pconnect' => TRUE,
    'db_debug' => TRUE,
    'cache_on' => FALSE,
    'cachedir' => APPPATH .'cache',
    'char_set' => 'utf8',
    'dbcollat' => 'utf8_general_ci',
    'swap_pre' => '',
    'autoinit' => TRUE,
    'stricton' => FALSE
);
$active_group = SELECTED_DB;

然后我将使用 Hook 来定义SELECTED_DB，或者在default_controller 中：

if($this->session->userdata('loggedin') == TRUE){
    define('SELECTED_DB', $this->session->userdata('selecdb'));
}
else{
   $selected_db = $this->uri->segment(2); // or use $this->input->get('db');
   $this->load->database($selected_db);
   defined('SELECTED_DB') 
      || define('SELECTED_DB', $selected_db);

   // Do login
}