从 JSON 数组拼接或删除元素列表

Question

我有一个这样的 REST API 的 JSON 数组输出，我正在使用 ng-repeat 在 HTML 上显示这些项目。

var searchresponse = [{
    "items": [{
        "employeeId": "ABC",
        "type": "D",
        "alive": "Yes"

    }, {
        "employeeId": "DEF",
        "type": "D",
        "alive": "Yes"

    }, {
        "employeeId": "NPK",
        "type": "D",
        "alive": "Yes"

    }, {
        "employeeId": "PKN",
        "type": "A",
        "alive": "Yes"
    }],
    "more": false
}];

当用户尝试使用 selectall/single select 删除时，我正在调用 REST API 以从 db 中删除员工 ID。一旦我得到一个成功的响应，我计划拼接/删除用户从视图中选择的值。我想从搜索响应中删除以下employeeid 及其类型，alive 删除

 var data1=["ABC","NPK"];

无论 data1 有什么对应的细节，都应该从 searchresponse 中删除

Answer 1

您只需使用splice 方法从employeeId 在data1 中的items 数组中删除每个项目。

参考资料

• splice method.

• indexOf method

var searchresponse = [{
    "items": [{
        "employeeId": "ABC",
        "type": "D",
        "alive": "Yes"

    }, {
        "employeeId": "DEF",
        "type": "D",
        "alive": "Yes"

    }, {
        "employeeId": "NPK",
        "type": "D",
        "alive": "Yes"

    }, {
        "employeeId": "PKN",
        "type": "A",
        "alive": "Yes"
    }],
    "more": false
}];
var data1=["ABC","DEF"];
var items=searchresponse[0].items;
var i=items.length;
while (i--) {
    if(data1.indexOf(items[i].employeeId)!=-1){
        items.splice(i,1);
    }
}
console.log(searchresponse[0].items);