【发布时间】:2019-02-06 11:21:13
【问题描述】:
我正在尝试将 jsonresult 数据绑定到来自数据库的标签文本,但它不起作用.. 我已经发布了脚本代码,它将获取下拉列表选择的值并传递给 actionresult,然后结果数据作为 jsonresult 传递
<script>
function getOutletDetails() {
debugger;
var centreName = $("#ddl_Outlet").find("option:selected").text();
$.ajax
({
url: "@Url.Action("OutletDetails", "AddTickets", new {area="Common"})",
type: 'POST',
datatype: 'application/json',
contentType: 'application/json',
data: JSON.stringify({ centreName: +centreName }),
success: function (result) {
$("#lblTelephone1").text(result.Telephone_01);
},
error: function () {
alert("Whooaaa! Something went wrong..")
},
});
}
</script>
控制器代码
[HttpPost]
public ActionResult OutletDetails(string centreName)
{
List<tbl_Centre> lstcity = new List<tbl_Centre>();
// int id1 = Convert.ToInt32(id);
//ViewBag.Id = id;
lstcity = (objbs.CentreBs.GetAll().Where(x => x.CentreName == centreName)).ToList<tbl_Centre>();
var result = JsonConvert.SerializeObject(lstcity, Formatting.None, new JsonSerializerSettings() { ReferenceLoopHandling = ReferenceLoopHandling.Ignore });
return Json(result, JsonRequestBehavior.AllowGet);
}
【问题讨论】:
-
Jsonresult 未绑定到标签
-
你能在这里提供你的html和json结果吗?
-
是的,这是 html
-
-
控制器代码
标签: javascript model-view-controller jsonresult