【问题标题】:Parsley JS Not Equal To Multiple IDsParsley JS 不等于多个 ID
【发布时间】:2020-09-09 18:11:31
【问题描述】:

我有一个包含多个选择框的表单,需要确保没有在其中任何一个中设置相同的值。例如,如果选择框 1 设置为 2,并且选择框 4 也设置为 2,我应该会收到错误消息。我可以使用单个 ID 进行此操作,但无法使用逗号分隔的多个 ID。

另一个要求是,一旦用户纠正了错误并且无需再次提交表单,我需要 Parsley 验证 .change。

仅适用于单个 ID 的代码是:

window.Parsley.addValidator("notequalto", {
    requirementType: "string",
    validateString: function(value, element) {
        return value !== $(element).val();
    }
});

我目前拥有的验证码是:

var validating;

$("#postorg").parsley();

$('#series_post_order1').change(()=>{
 if(!validating) return; $("#postorg").parsley().validate({group:'postorder'});
});
$('#series_post_order2').change(()=>{
 if(!validating) return; $("#postorg").parsley().validate({group:'postorder'});
});
$('#series_post_order3').change(()=>{
 if(!validating) return; $("#postorg").parsley().validate({group:'postorder'});
});
$('#series_post_order4').change(()=>{
 if(!validating) return; $("#postorg").parsley().validate({group:'postorder'});
});

window.Parsley.addValidator("notequalto", {
      validateMultiple: function(values) {
        return values.length > 0;
      },
    requirementType: "string",
    validateString: function(value, element) {
     var els=element.split(',');
     for(let i=0;i<els.length;i++){
       if (jQuery(els[i]).val()){
        return value !== $(element).val();
       }
     }
      return true;
   },
   priority: 33
});

表格如下所示:

<form name="series_edit_postorg" id="postorg" method="post" action="series_postorg">

<div class="formbig-mobile">

<select name="series_post_order1" class="select" id="series_post_order1" data-parsley-group="postorder" data-parsley-notequalto="#series_post_order2,#series_post_order3,#series_post_order4" data-parsley-notequalto-message="Each post must have a different number">
<option value="1" selected>1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>

<select name="series_post_order2" class="select" id="series_post_order2" data-parsley-group="postorder" data-parsley-notequalto="#series_post_order1,#series_post_order3,#series_post_order4" data-parsley-notequalto-message="Each post must have a different number">
<option value="2" selected>2</option>
<option value="1">1</option>
<option value="3">3</option>
<option value="4">4</option>
</select>
</div>

<select name="series_post_order3" class="select" id="series_post_order3" data-parsley-group="postorder" data-parsley-notequalto="#series_post_order1,#series_post_order2,#series_post_order4" data-parsley-notequalto-message="Each post must have a different number">
<option value="3" selected>3</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="4">4</option>
</select>
</div>

<select name="series_post_order4" class="select" id="series_post_order4" data-parsley-group="postorder" data-parsley-notequalto="#series_post_order1,#series_post_order2,#series_post_order3" data-parsley-notequalto-message="Each post must have a different number">
<option value="4" selected>4</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
</select>
</div>

<input type="submit" name="submit" value="UPDATE" class="selectbutton">

</form>

【问题讨论】:

    标签: javascript jquery forms validation parsley.js


    【解决方案1】:

    这是解决这个问题的答案:

    var validating;
    
    $("#postorg").parsley();
    
    $('.select').change(()=>{
    if(!validating) return; $("#postorg").parsley().validate({group:'postorder'});
    });
    
    window.Parsley.addValidator("notequalto", {
          validateMultiple: function(values) {
            return values.length > 0;
          },
        requirementType: "string",
        validateString: function(value, requirement) {
          validating = true;
          var $otherElements = $(requirement);
          var duplicateFound = false;
          
          $otherElements.each(function(){
            duplicateFound = duplicateFound || this.value === value;
          });
          
          return !duplicateFound;
       },
       priority: 33
    });

    【讨论】:

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