Beautifulsoup 获取 span 内容答案

【问题标题】：Beautifulsoup get span contentBeautifulsoup 获取 span 内容
【发布时间】：2014-03-07 19:50:14
【问题描述】：

我已经解析了 html 页面：使用 beautifulsoup

user_page = urllib2.urlopen(user_url)
souping_page = bs(user_page)
badges = souping_page.body.find('div', attrs={'class': 'badges'})

在这之后我的badges 对象看起来像这样：

<span><span title="9 gold badges"><span class="badge1"></span><span class="badgecount">9</span></span><span title="38 silver badges"><span class="badge2"></span><span class="badgecount">38</span></span><span title="56 bronze badges"><span class="badge3"></span><span class="badgecount">56</span></span></span>

现在我想从中提取示例9 gold badges，38 silver badges，我尝试使用badges.span.span，但这不起作用。

【问题讨论】：

标签： python html beautifulsoup html-parsing

【解决方案1】：

从badges 中获取父span，使用find_all() 和recursive=False 查找内部所有顶级跨度：

from bs4 import BeautifulSoup


page = """<div class="badges">
<span>
    <span title="9 gold badges"><span class="badge1"></span><span class="badgecount">9</span></span>
    <span title="38 silver badges"><span class="badge2"></span><span class="badgecount">38</span></span>
    <span title="56 bronze badges"><span class="badge3"></span><span class="badgecount">56</span></span>
</span>
</div>"""

soup = BeautifulSoup(page)
badges = soup.body.find('div', attrs={'class': 'badges'})
for span in badges.span.find_all('span', recursive=False):
    print span.attrs['title']

打印：

9 gold badges
38 silver badges
56 bronze badges

希望对您有所帮助。

【讨论】：