需要 XML 解析分号 - 仅当用 &amp 替换 & 时答案

【问题标题】：XML parsing semicolon expected - only when replacing & with &amp需要 XML 解析分号 - 仅当用 &amp 替换 & 时
【发布时间】：2016-12-12 14:56:28
【问题描述】：

我有以下查询，它有效：

DECLARE @Combined VARCHAR(MAX)

SET @Combined = 'mac cheese';

DECLARE @KeyTable TABLE (Keyword VARCHAR(MAX))
INSERT INTO @KeyTable
SELECT @Combined

IF OBJECT_ID('tempdb..#Temp') IS NOT NULL
    DROP TABLE #Temp

SELECT LTRIM(RTRIM(m.n.value('.[1]','varchar(8000)'))) AS Keyword
    INTO #Temp
FROM
(
SELECT CAST('<XMLRoot><RowData>' + REPLACE(Keyword,',','</RowData><RowData>') + '</RowData></XMLRoot>' AS XML) AS x
FROM @KeyTable
)t
CROSS APPLY x.nodes('/XMLRoot/RowData')m(n);

SELECT * FROM #Temp

当我尝试向 @Combined 添加一个 & 符号时，它会给出一个特殊字符错误：

DECLARE @Combined VARCHAR(MAX)

SET @Combined = 'mac & cheese';

DECLARE @KeyTable TABLE (Keyword VARCHAR(MAX))
INSERT INTO @KeyTable
SELECT @Combined

IF OBJECT_ID('tempdb..#Temp') IS NOT NULL
    DROP TABLE #Temp

SELECT LTRIM(RTRIM(m.n.value('.[1]','varchar(8000)'))) AS Keyword
    INTO #Temp
FROM
(
SELECT CAST('<XMLRoot><RowData>' + REPLACE(Keyword,',','</RowData><RowData>') + '</RowData></XMLRoot>' AS XML) AS x
FROM @KeyTable
)t
CROSS APPLY x.nodes('/XMLRoot/RowData')m(n);

SELECT * FROM #Temp

所以我添加了一些代码来用&amp 替换＆符号，我得到一个分号错误：

DECLARE @Combined VARCHAR(MAX)

SET @Combined = 'mac & cheese'

SET @Combined = REPLACE(@Combined, '&', '&amp')

DECLARE @KeyTable TABLE (Keyword VARCHAR(MAX))

INSERT INTO @KeyTable
SELECT @Combined;

IF OBJECT_ID('tempdb..#Temp') IS NOT NULL
    DROP TABLE #Temp

SELECT LTRIM(RTRIM(m.n.value('.[1]','varchar(8000)'))) AS Keyword
    INTO #Temp
FROM
(
SELECT CAST('<XMLRoot><RowData>' + REPLACE(Keyword,',','</RowData><RowData>') + '</RowData></XMLRoot>' AS XML) AS x
FROM @KeyTable
)t
CROSS APPLY x.nodes('/XMLRoot/RowData')m(n);

SELECT * FROM #Temp

我尝试将分号移动到不同的位置，甚至添加更多位置，但它不起作用。任何人都可以提供任何帮助，我们将不胜感激！

【问题讨论】：

所有实体转义字符串以分号结尾：REPLACE(@Combined, '&', '&amp;') - 另见stackoverflow.com/questions/1091945/…
哇...这么简单...谢谢。随时发布作为答案，我会同意
@AlexK。不，不应该开始手动替换禁用字符...

标签： sql-server xml-parsing

【解决方案1】：

不，你不应该开始自己替换特殊字符！

下次您的字符串包含< 或-> 时会再次中断。

让FOR XML PATH()为你干活：

SELECT 'This is pure text: ' + 'mac & cheese,<test1>,"test2"';
SELECT 'This is encoded: ' + (SELECT 'mac & cheese,<test1>,"test2"' AS [*] FOR XML PATH(''))

第二个结果：This is encoded: mac &amp; cheese,&lt;test1&gt;,"test2"

更新您的代码：

你唯一需要改变的是使用(SELECT ... FOR XML PATH())而不是naked Keyword

DECLARE @KeyTable TABLE (Keyword VARCHAR(MAX))
INSERT INTO @KeyTable VALUES('mac & cheese,<test1>,"test2"');

SELECT LTRIM(RTRIM(m.n.value('.[1]','varchar(8000)'))) AS Keyword
FROM
(
SELECT CAST('<XMLRoot><RowData>' + REPLACE((SELECT Keyword AS [*] FOR XML PATH('')),',','</RowData><RowData>') + '</RowData></XMLRoot>' AS XML) AS x
FROM @KeyTable
)t
CROSS APPLY x.nodes('/XMLRoot/RowData')m(n);

这将隐式替换所有禁用字符...

结果

mac & cheese
<test1>
"test2"

【讨论】：