【发布时间】:2016-10-20 04:56:33
【问题描述】:
我想将 XML 解析到我的 Android 应用程序。我试过一个教程。在这里它使用 DOMParser。应用程序中没有错误。但它没有显示 XML 输出。请帮我解决问题。这是我到目前为止所尝试的。
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
LinearLayout layout = new LinearLayout(this);
TextView name[];
TextView website[];
TextView category[];
try {
URL url = new URL(
"http://www.androidpeople.com/wp-content/uploads/2010/06/example.xml");
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new InputSource(url.openStream()));
doc.getDocumentElement().normalize();
NodeList nodeList = doc.getElementsByTagName("item");
name = new TextView[nodeList.getLength()];
website = new TextView[nodeList.getLength()];
category = new TextView[nodeList.getLength()];
for (int i = 0; i < nodeList.getLength(); i++) {
Node node = nodeList.item(i);
name[i] = new TextView(this);
website[i] = new TextView(this);
category[i] = new TextView(this);
Element fstElmnt = (Element) node;
NodeList nameList = fstElmnt.getElementsByTagName("name");
Element nameElement = (Element) nameList.item(0);
nameList = nameElement.getChildNodes();
name[i].setText("Name = "
+ ((Node) nameList.item(0)).getNodeValue());
NodeList websiteList = fstElmnt.getElementsByTagName("website");
Element websiteElement = (Element) websiteList.item(0);
websiteList = websiteElement.getChildNodes();
website[i].setText("Website = "
+ ((Node) websiteList.item(0)).getNodeValue());
category[i].setText("Website Category = "
+ websiteElement.getAttribute("category"));
layout.addView(name[i]);
layout.addView(website[i]);
layout.addView(category[i]);
}
} catch (Exception e) {
System.out.println("XML Pasing Excpetion = " + e);
}
setContentView(layout);
}
【问题讨论】:
-
你看到了什么?
-
只有一个空白活动
-
您是否在 AndroidManifest.xml 中定义了 Internet 权限?
-
@Haresh Chhelana- 是的,已经在 Manifest 中定义了它。
-
您正在主线程上调用服务器请求
标签: android xml-parsing domparser