在 python 中使用关键字访问 youtube api答案

【问题标题】：access youtube api using keyword in python在 python 中使用关键字访问 youtube api
【发布时间】：2015-06-04 12:23:16
【问题描述】：

我想为我的下一个项目访问 youtube api，但我不知道如何使用已经可用的 python 代码：

我使用的代码是

#!/usr/bin/python

from apiclient.discovery import build
from apiclient.errors import HttpError
from oauth2client.tools import argparser


# Set DEVELOPER_KEY to the API key value from the APIs & auth > Registered apps
# tab of
#   https://cloud.google.com/console
# Please ensure that you have enabled the YouTube Data API for your project.
DEVELOPER_KEY = "Replaced_my_API_key"
YOUTUBE_API_SERVICE_NAME = "youtube"
YOUTUBE_API_VERSION = "v3"

def youtube_search(options):
  youtube = build(YOUTUBE_API_SERVICE_NAME, YOUTUBE_API_VERSION,
    developerKey=DEVELOPER_KEY)

  # Call the search.list method to retrieve results matching the specified
  # query term.
  search_response = youtube.search().list(
    q=options.q,
    part="id,snippet",
    maxResults=options.max_results
  ).execute()

  videos = []
  channels = []
  playlists = []

  # Add each result to the appropriate list, and then display the lists of
  # matching videos, channels, and playlists.
  for search_result in search_response.get("items", []):
    if search_result["id"]["kind"] == "youtube#video":
      videos.append("%s (%s)" % (search_result["snippet"]["title"],
                                 search_result["id"]["videoId"]))
    elif search_result["id"]["kind"] == "youtube#channel":
      channels.append("%s (%s)" % (search_result["snippet"]["title"],
                                   search_result["id"]["channelId"]))
    elif search_result["id"]["kind"] == "youtube#playlist":
      playlists.append("%s (%s)" % (search_result["snippet"]["title"],
                                    search_result["id"]["playlistId"]))

  print "Videos:\n", "\n".join(videos), "\n"
  print "Channels:\n", "\n".join(channels), "\n"
  print "Playlists:\n", "\n".join(playlists), "\n"


if __name__ == "__main__":
    argparser.add_argument("--q", help="Search term", default="Google")
    argparser.add_argument("--max-results", help="Max results", default=25)
    args = argparser.parse_args()


  try:
    youtube_search(args)
  except HttpError, e:
    print "An HTTP error %d occurred:\n%s" % (e.resp.status, e.content)

我想访问视频 ID

我不知道应该在哪里传递我的搜索字符串作为参数。

提前致谢，

【问题讨论】：

标签： python-2.7 video youtube

【解决方案1】：

 argparser.add_argument("--q", help="Search term", default="Google")

在这里，您应该将您的字符串与您想要搜索的内容放在一起，而不是“Google”。

假设您要查找《巫师 3》视频。

to_search = "Witcher 3"
argparser.add_argument("--q", help="Search term", default=to_search)

【讨论】：