删除所有 Href 和 youtube URL 并获取 ID

Question

$article = ('<p>In show business it is all about the extremes. For example the people
 below earn a whole load of money thanks to their appearance and it is not at all 
beautiful. They are some of the ugliest models but nevertheless they still work in 
full swing. They get hired in movies, commercials, and anywhere where an ugly guy 
(or a girl) is needed , and if you’re just plane average and you still wish to 
work, well then you should probably do something extreme with your body like the 
lizard man, for example.</p></a>
<a href="http://www.youtube.com/watch?v=eauCiY1MmZU">
    http://www.youtube.com/watch?v=eauCiY1MmZU
</a>

function tubeCodeEmbed( $vCode ) {
   return $vCode;
}

$search = '/\s*[a-zA-Z\/\/:\.]*youtube.com\/watch\?v=([a-zA-Z0-9\-_]+)([a-zA-Z0-9\/\*\-\_\?\&\;\%\=\.]*)/i';
$article = preg_replace($search, tubeCodeEmbed("$1"), $article);
echo $article;

这是我到目前为止所拥有的......它可以工作，只是它不会从包含 youtube 的字符串中删除 href。

我想要的输出

在演艺界，一切都是关于极端的。例如人们 由于他们的外表，下面赚了一大笔钱 一点都不漂亮。 joeCiY1MmZU 他们是最丑的模特 但尽管如此，他们仍然如火如荼地工作。他们被录用 电影、广告以及任何有丑男（或女孩）的地方 需要，如果你只是平庸而你仍然想工作， 那么你可能应该对你的身体做一些极端的事情，比如 例如蜥蜴人。奇数CiY1MmZU eauCiY1MmZU

---

注意输出中的 ID ...没有来自 youtube 的 url 或 href 标签

Answer 1

$article=explode("?v=",$article);
$article=explode("\"",$article[1]);
$youtube_id=$article[0];

$youtube_id 将返回视频的 id

Answer 2

看看这段代码能不能用。

工作PHP Fiddle

<?php
$article = '<p>In show business it is all about the extremes. For example the people
 below earn a whole load of money thanks to their appearance and it is not at all 
beautiful. They are some of the ugliest models but nevertheless they still work in 
full swing. They get hired in movies, commercials, and anywhere where an ugly guy 
(or a girl) is needed , and if you’re just plane average and you still wish to 
work, well then you should probably do something extreme with your body like the 
lizard man, for example.</p><a href="http://www.youtube.com/watch?v=eauCiY1MmZU">http://www.youtube.com/watch?v=eauCiY1MmZU</a>';


function get_id($matches){
  parse_str( parse_url( $matches[2], PHP_URL_QUERY ), $tArr );
  return " ".$tArr["v"];
}
$string = preg_replace("/<p[^>]*?>/", "",$article);
$string = str_replace("</p>", "", $string);
$string = preg_replace_callback("#<a(.+?)>(.+?)</a>#is", "get_id", $string);

echo $string;

?>

输出：

在演艺界，一切都是关于极端的。例如人们 由于他们的外表，下面赚了一大笔钱 一点都不漂亮。它们是一些最丑陋的模型，但 尽管如此，他们仍然如火如荼地工作。他们被电影​​聘用， 广告，以及任何需要丑男（或女孩）的地方， 如果你只是平庸而你仍然想工作，那么 你可能应该对你的身体做一些极端的事情，比如 以蜥蜴人为例。 eauCiY1MmZU eauCiY1MmZU

Answer 3

//Strip all youtube links from the $article.
    if ((preg_match('/http:\/\/www\.youtube\.com\/watch\?v=[^&]+/',$article->text))==true) {
    $article->text = preg_replace('/(<a [^>]+)>(http:\/\/*.*.youtube.*)  <\/a>|iU/iU', '$2', $article->text);
    $ychar = '/\s*[a-zA-Z\/\/:\.]*youtube.com\/watch\?v=([a-zA-Z0-9\-_]+)([a-zA-Z0-9\/\*\-\_\?\&\;\%\=\.]*)/i';
    $article->text = preg_replace($ychar, $this->youtubeCodeEmbed("$1"), $article->text);
    return true;
//Strip all vimeo links from the $article.
} elseif ((preg_match('/http:\/\/(.*?)vimeo\.com\/[0-9]+/', $article->text))==true) {
    $article->text = preg_replace('/(<a [^>]+)>(http:\/\/*.*.vimeo.*)<\/a>|iU/iU', '$2', $article->text);
    $vchar = '/\s*[a-zA-Z\/\/:\.]*vimeo.com\/([0-9\-_]+)([0-9\/\*\-\_\?\&\;\%\=\.]*)/i';
    $article->text = preg_replace($vchar, $this->vimeoCodeEmbed('$1'), $article->text);
    return true;
    } else {
return false;
}

}

经过一些挖掘和探索，这是一个可行的解决方案，并且效果很好。 首先 preg_replace 删除给定域的所有 href URL，然后...删除其他 preg_replace 中的其余部分