在php数组中删除过去的日期？ [复制]

Question

正在努力解决这个问题......

$dates_list 输出这个数组

Array
(
    [0] => Array
        (
            [0] => Array
                (
                    [event_date] => 2020-11-19 00:00:00
                    [event_start_time] => 13:07:00
                    [event_end_time] => 17:07:00
                )

            [1] => Array
                (
                    [event_date] => 2020-06-17 00:00:00
                    [event_start_time] => 10:07:00
                    [event_end_time] => 17:07:00
                )

            [2] => Array
                (
                    [event_date] => 2020-03-05 00:00:00
                    [event_start_time] => 15:46:00
                    [event_end_time] => 20:46:00
                )

        )

    [1] => Array
        (
            [0] => Array
                (
                    [event_date] => 2020-07-07 00:00:00
                    [event_start_time] => 20:10:00
                    [event_end_time] => 20:10:00
                )

            [1] => Array
                (
                    [event_date] => 2020-03-13 00:00:00
                    [event_start_time] => 20:10:00
                    [event_end_time] => 20:10:00
                )

        )

)

我创建了$now，它显示了当前的日期和时间

$now = date("Y-m-d h:i:s");
// 2020-03-12 09:17:42

@RoboRobok 提供了这个答案，当数组没有嵌套时它可以工作

$dates_filtered = array_filter($dates_list,
            function ($date_entry) use ($now) {
                return $date_entry['event_date'] >= $now;
            }
        );

如何访问嵌套数组以从数组中删除过去的日子？

Answer 1

使用array_filter:

$result = array_filter(
    $dates_list,
    function ($date_entry) use ($now) {
        $date = substr($date_entry['event_date'], 0, 10);
        $time = $date_entry['event_start_time'];

        return "$date $time" >= $now;
    }
);

Answer 2

试试这个

foreach($dates_list as $i=>$dateItem){
   if (strtotime($dateItem['event_date']) < time()) {
    // past date
    unset($dates_list[$i]);
}

}
print_r($dates_list);