我正在使用 selectpicker 我想编辑来自数据库的数据，但所有选项都已被选中

Question

all categories coming selected which i want to see only which information is coming from database. 对不起我的英语。

<div class="col-xs-4">
  <label>Categories</label>
    <!-- SEARCH JS find (selectpicker) -->
  <select name="product_cat" id="product_cat" class="form-control selectpicker" data-live-search="true" multiple>
    <?php 

    while($productcatcek=$productcatsor->fetch(PDO::FETCH_ASSOC)) {

    ?>
    
      <option selected="">
        <dl>
          <dt ><?php
          if ($productcatcek['pcat_id']==$productcatcek['pcat_id']) {
             echo $productcatcek['pcat_name'];
           } 
          ?> - </dt>
          <dd <?php echo $productcatcek['pcat_id']==$productcatcek['pcat_id'] ? 'selected=""' : '' ?>><?php echo $productcatcek['spcat_name']; ?></dd>
        </dl>
      </option>
    
  <?php } ?>
  </select>
  <!-- SEARCH Finish -->
</div>

解决方案

<option value="<?php echo $productcatcek['spcat_id']; ?>" <?php echo $productcatcek['spcat_id']==$productcek['product_cat'] ? 'selected=""' : '' ?>>
  <dl>
   <dt><?php echo $productcatcek['pcat_name']; ?> - </dt>
   <dd><?php echo $productcatcek['spcat_name']; ?></dd>
  </dl>
 </option>

Answer 1

selected 属性只需要存在于您的<option> 元素上；它不需要有值。要不选择 <option>，只需不包含该属性