【发布时间】:2020-02-28 14:28:30
【问题描述】:
我想使用 volley 库将信息发送到服务器并将其保存到表中。但是运行应用后,表中没有数据存储。
你能说出哪一部分是错的吗? (我做了网站上说的大部分事情,但我的问题没有解决)
cart.java
public class cart extends AppCompatActivity {
Button Add;
private static final String url="http://localhost/test/addpost.php";
Faculty items;
JSONArray myarray;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_cart);
Add=findViewById(R.id.btn_basket_pay);
dbHandler dbh = new dbHandler(this);
dbh.open();
items=new Faculty();
JSONObject JSONestimate = new JSONObject();
myarray = new JSONArray();
RecyclerView recyclerView = (RecyclerView) findViewById(R.id.rec);
final FacultyAdapter facultyAdapter = new FacultyAdapter(this,dbh.display());
recyclerView.setLayoutManager(new LinearLayoutManager(this,LinearLayoutManager.VERTICAL,false));
recyclerView.setAdapter(facultyAdapter);
dbh.close();
for (int i = 0; i < facultyAdapter.getItemCount(); i++) {
try {
JSONestimate.put("name:" + String.valueOf(i + 1), facultyAdapter.getJSONObject());
myarray.put(facultyAdapter.getJSONObject());
} catch (JSONException e) {
e.printStackTrace();
}
}
Log.d("JSONobject: ", JSONestimate.toString());
Log.d("JSONArray : ", myarray.toString());
Add.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
RequestQueue queue = Volley.newRequestQueue(getApplicationContext());
StringRequest stringRequest=new StringRequest(Request.Method.GET, url, new
Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.d("onResponse", "o");
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.d("onErrorResponse", "o");
}
}){
@Override
public Map<String,String> getParams(){
Map<String,String> params=new HashMap<>();
params.put("jsonarray",myarray.toString());
return params;
}
};
queue.add(stringRequest);
Toast.makeText(cart.this,"success",Toast.LENGTH_SHORT).show();
}
});
}}
我用邮递员程序检查了 php 代码,它工作正常。
addpost.php
<?php
if($_SERVER['REQUEST_METHOD']=='GET'){
require_once('dbConnect.php');
$name = $_GET['name'];
$price= $_GET['price'];
$id = $_GET['id'];
$response = array();
$server_ip = gethostbyname(gethostname());
$sql = "INSERT INTO tblcart (id,name,price) VALUES ('$id','$name','$price')";
try {
if (mysqli_query($cnn,$sql)) {
$response = "done";
}else{
$response = "error";
}
} catch (Exception $e) {
$response = "error";
}
echo $response;
}
?>
【问题讨论】:
-
把
var_dump($_GET);放在PHP代码的顶部,看看你得到了什么。 -
@JayBlanchard 但并没有解决问题
-
它不应该解决问题,它应该让我们看看你在 PHP 代码中得到了什么。它返回了什么?
-
@JayBlanchard 表中没有要返回的值,但是当我手动添加值时,它会显示现有值。
标签: php android android-volley