ValueError：日期超出月份的范围-如何使用不同月份的日期进行数学运算[重复]

Question

我有一个 python 程序，它将一年中的星期作为输入，格式为：YYYY-W# 该程序使用此输入为一周中的每一天生成值并将数据输出到 Excel 文件。

我收到错误消息：ValueError: day is out of range for month，我意识到当一周中的几天在不同的月份（例如，星期一、星期二是 11 月，星期三、星期四等是 12 月）时，我会收到此错误。

以下代码是我获取星期几的值的方式：

monday = datetime.datetime.strptime(week + '-1', '%G-W%V-%u')
tuesday = datetime.datetime(monday.year, monday.month, monday.day - monday.weekday() + 1)
wednesday = datetime.datetime(monday.year, monday.month, monday.day - monday.weekday() + 2)
thursday = datetime.datetime(monday.year, monday.month, monday.day - monday.weekday() + 3)
friday = datetime.datetime(monday.year, monday.month, monday.day - monday.weekday() + 4)
saturday = datetime.datetime(monday.year, monday.month, monday.day - monday.weekday() + 5)
sunday = datetime.datetime(monday.year, monday.month, monday.day - monday.weekday() + 6)

如果整周都在同一个月内，此代码可以正常工作，有没有办法修改它以考虑可能不在同一个月内的周？

Answer 1

使用timedelta:

tuesday = monday + datetime.timedelta(days=1)
wednesday = ... # (and so on)

Answer 2

结合Get date from week number的（轻微）重复问题中的答案和Rustam A.的答案：

from datetime import datetime, timedelta

d = "2021-W48"
monday = datetime.strptime(d + "-1", "%Y-W%W-%w")
week = [monday + timedelta(days=x) for x in range(7)]

print(week)
# [datetime.datetime(2021, 11, 29, 0, 0), datetime.datetime(2021, 11, 30, 0, 0), datetime.datetime(2021, 12, 1, 0, 0), datetime.datetime(2021, 12, 2, 0, 0), datetime.datetime(2021, 12, 3, 0, 0), datetime.datetime(2021, 12, 4, 0, 0), datetime.datetime(2021, 12, 5, 0, 0)]

（编辑：使用 ISO 周时，请像您一样使用 %G-W%V-%u）