【发布时间】:2016-07-18 13:05:22
【问题描述】:
我正在尝试设置一个用户个人资料,您可以在其中输入技能。输入技能并将它们保存在数据库中已经可以了。现在我想让用户有机会通过单击按钮删除其中的每一个。我尝试在 URL 中单击按钮时发布每个技能的 ID,并在我的视图中读出它以获取该项目并将其删除,但这并不像我想的那样工作,我无法找出原因......
我的看法
def profile_settings(request, id=None):
# get logged in user object from session
user_id = request.user.id
# get related userprofile
userprofile = UserProfile.objects.get(pk=user_id)
# get all skills of the userprofile
user_skills = Skill.objects.filter(user=userprofile)
if request.method == 'POST':
form = SkillForm(request.POST)
if 'delete-skill' in request.POST:
if id:
print(id)
skill = Skill.objects.get(pk=id).delete()
elif 'add-skill' in request.POST:
if form.is_valid():
# get data from form
name = form.cleaned_data['name']
category = form.cleaned_data['category']
rating = form.cleaned_data['rating']
# create new skill object for a user
new_skill = Skill(name=name, category=category, rating=rating, user=userprofile)
# save it in the database
new_skill.save()
else:
form = SkillForm()
return render(request, 'profile-settings.html', {'skillform': form, 'existing_skills': user_skills})
我的网址
urlpatterns = [
url(r'^landing', views.landing, name='landing'),
url(r'^neuigkeiten', views.news, name='news'),
url(r'^profileinstellungen/', views.profile_settings, name='profileinstellungen'),
url(r'^profileinstellungen/(?P<id>\d+)/$', views.profile_settings, name='profileinstellungen'),
]
我的模板
{% extends 'base.html' %}
{% block content %}
<form method="post" style="margin-top: 300px">
{% csrf_token %}
{{ skillform }}
<input type="submit" value="Hinzufügen" name="add-skill "/>
</form>
<form method="post">
{% csrf_token %}
<ul>
{% for skill in existing_skills %}
<li>{{ skill.name }}</li>
<input href="{% url 'profileinstellungen' id=skill.id%}" type="submit" value="Löschen" name="delete-skill"/>
{% endfor %}
</ul>
</form>
{% endblock %}
它不会在 URL 中发布技能的 ID。有其他方法吗?
【问题讨论】:
-
您是否遇到任何具体错误。
-
好吧,当我点击删除按钮时,技能的 ID 没有在 url 中传递,所以什么也没有发生......
标签: python django django-models django-templates django-views