【发布时间】:2019-03-08 12:02:12
【问题描述】:
我的 mysql 记录中保存了如下文本:
Handmade item
Materials: wooden handcrafted handle, professional laser engraved rubber, brown
cardboard special gift box, authorial stamp passport
上面的文字代表了我的配件模型的概述,即:
from django.db import models
class Accessory(models.Model):
img = models.ImageField(upload_to='accessories/', default='accessories/no.png')
name = models.CharField(max_length=50)
price = models.DecimalField(max_digits=5, decimal_places=2)
img_inside1 = models.ImageField(upload_to='accessories/', default='accessories/no.png', blank=True)
img_inside2 = models.ImageField(upload_to='accessories/', default='accessories/no.png', blank=True)
img_inside3 = models.ImageField(upload_to='accessories/', default='accessories/no.png', blank=True)
title = models.CharField(max_length=50)
overview = models.TextField(blank=True)
description = models.TextField()
我想在<li>标签中显示每一行
看起来像这样:
<ul>
<li><p>Handmade item</p></li>
<li><p>Materials: wooden handcrafted handle,
professional laser engraved rubber, brown cardboard
special gift box, authorial stamp passport</p>
</li>
</ul>
使用linebreaks 过滤器将不会应用<ul> 默认样式(显示项目符号)。提前致谢!
【问题讨论】:
-
python代码在哪里?
-
这里是配件相关的型号
from django.db import models class Accessory(models.Model): overview = models.TextField(blank=True) description = models.TextField() -
请提出这个python代码
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我已经添加了我的python代码
标签: python django python-3.x django-templates