【发布时间】:2013-04-22 11:09:49
【问题描述】:
我正在为 jquery 使用 X-Editable 插件。我有两个通过 ajax 动态提供数据的选择字段。这是我的代码:
字段:
<td class="center">
<a href="#" data-name="'.$res['mid'].'" class="zone">'.$zonename.'</a>
</td>
<td class="center">
<a href="#" data-name="'.$res['mid'].'" class="area" data-zona="'.$zoneuid.'">'.$areaname.'</a>
</td>
还有 jQuery:
$('a.zone').editable({
type: 'select',
url: '../admin/callbacks/quickEdit.php?t=zone',
pk: 1,
showbuttons: true,
source: function() {
var result;
$.ajax({
url: '../admin/callbacks/jsonDataList.php',
data: {t: 'zone'},
type: 'GET',
global: false,
async: false,
dataType: 'json',
success: function(data) {
result = data;
}
});
return result;
},
success: function(response, newValue) {
$(this).parent().siblings('td').children('a.area').data('zona', newValue);
console.log(response, newValue);
}
});
$('a.area').editable({
type: 'select',
pk: 1,
url: '../admin/callbacks/quickEdit.php?t=area',
showbuttons: true,
source: function() {
var result;
var zona = $(this).data('zona');
$.ajax({
url: '../admin/callbacks/jsonDataList.php',
data: {t: 'area', zone: zona},
type: 'GET',
global: false,
async: false,
dataType: 'json',
success: function(data) {
result = data;
}
});
return result;
},
success: function(response, newValue) {
console.log(response);
}
});
我想要做的是:当他们更改 $('a.zone') 的值时,我希望 $('a.area') 重新加载 ajax 数据。我该怎么做?
【问题讨论】:
标签: jquery ajax jquery-plugins twitter-bootstrap