【发布时间】:2020-08-01 23:54:34
【问题描述】:
如何读取 Item 元素的所有子项并将其存储在对象中
这是我的示例 xml 文件
<People>
<Person>
<Name>Ben</Name>
<Items>
<Item>Pen</Item>
<Item>Paper</Item>
<Item>Books</Item>
</Items>
</Person>
<Person>
<Name>Alex</Name>
<Items>
<Item>Pencil</Item>
<Item>Eraser</Item>
</Items>
</People>
我用 getter 和 setter 创建了一个 Person 对象
public class Person{ // SAMPLE OBJECT
private String name; @getters and setters
private String item; @getters and setters
}
这是我的读取方法
public ArrayList<Person> getPeople(){
people = new ArrayList<>();
Person a = null;
if (Files.exists(peoplePath)) // prevent the FileNotFoundException
{
// create the XMLInputFactory object
XMLInputFactory inputFactory = XMLInputFactory.newFactory();
try
{
// create a XMLStreamReader object
FileReader fileReader =
new FileReader(peoplePath.toFile());
XMLStreamReader reader =
inputFactory.createXMLStreamReader(fileReader);
// read from the file
while (reader.hasNext())
{
int eventType = reader.getEventType();
switch (eventType)
{
case XMLStreamConstants.START_ELEMENT:
String elementName = reader.getLocalName();
if (elementName.equals("Person"))
{
a = new Person();
}
if (elementName.equals("Name"))
{
String name = reader.getElementText();
a.setName(name);
}
if (elementName.equals("Item"))
{
String item= reader.getElementText();
a.setItem(item);
}
break;
case XMLStreamConstants.END_ELEMENT:
elementName = reader.getLocalName();
if (elementName.equals("Person"))
{
people.add(a);
}
break;
default:
break;
}
reader.next();
}
}
catch (IOException | XMLStreamException e)
{
System.out.println(e);
return null;
}
}
return people;
}
此方法显示
本
亚历克斯
但如果我只使用类似代码获取项目,它会显示
书籍
橡皮擦
public static void displayPeople(){
ArrayList<Person> people = personDAO.getPeople();
People p = null;
StringBuilder sb = new StringBuilder();
for (int i = 0; i < people.size(); i++)
{
a = people.get(i);
sb.append(a.getName());
sb.append("\n");
}
System.out.println(sb.toString());
}
我想做这个输出
Ben
Pen
Paper
Book
Alex
Pencil
Eraser
【问题讨论】:
标签: java xml element xmlreader stax