搜索列表然后从其他列表中调用同一个地方[关闭]答案

【问题标题】：Searching lists then calling same place from other lists [closed]搜索列表然后从其他列表中调用同一个地方[关闭]
【发布时间】：2016-04-03 08:18:41
【问题描述】：

我希望我的程序搜索 resident 并且如果它是一个特定的值，它将打印来自其他列表的相同放置的数据。例如，在这种情况下，我希望它打印出来；

“名字叫艾伦，7岁，他们不住在原地”，

还有，

“名字叫玛格丽特，66岁，他们不住在原地”

name = ["Alan", "Susan", "Margaret"]
age = [7, 34, 66]
resident = [0, 1, 0]

if resident = 0:
    print ("name is {}, age is {} and they do not live in place".format(name[], age[]))

【问题讨论】：

Pythonic iteration over multiple lists in parallel

标签： python

【解决方案1】：

for person, ages, residency in zip(name,age,resident):
    if residency == 0:
        print("name is {0}, age is {1} and they do not live in place".format(person, ages))

zip 接受多个列表并返回一个元组列表。这是一个例子：

zip(name, age, resident)
>>>> [('Alan', 7, 0), ('Susan', 34, 1), ('Margaret', 66, 0)]

遍历每个元组非常容易。

【讨论】：

【解决方案2】：

考虑使用enumerate，它将提供迭代列表中的索引和项目：

>>> for i,x in enumerate(resident):
        if x == 0:
            print("name is {0}, age is {1} and they do not live in place".format(name[i], age[i]))


name is Alan, age is 7 and they do not live in place
name is Margaret, age is 66 and they do not live in place

【讨论】：

【解决方案3】：

可以使用常用的%s字符串替换：

name = ["Alan", "Susan", "Margaret"]
age = [7, 34, 66]
resident = [0, 1, 0]

if resident[0] == 0:print ("name is %s, age is %s and they do not live in place"%(name[0],age[0]))

【讨论】：