查找并显示前 n 个自然数的立方和

Question

我需要找到并显示前 n 个自然数的立方和，而我目前使用的代码似乎只能打印到我想要​​的范围。

最大是 20，它打印我的数字的立方体最多 20。我为求和编写的循环不起作用，通常会使程序崩溃。

任何有关如何制作它的帮助或想法，以便程序只对输入的数字进行立方，然后将这些立方相加，我们将不胜感激，请保持简单。

public class MyIntNumberr
{ // construct a myintnumber with one instance field n
    public MyIntNumberr(int n)
    {
        number = n;
    }

    public void calcCubeAndSum(int num)
    {

        if (num < 0)
        {
            System.out.println("that integer is invalid please try again");
            System.exit(0);
        }
        while (num >= 1 && num <= 20)
        {
            System.out.println(" " + num + "      " + Math.pow(num, 3));
            num = num + 1;
        }

    }

    // instance fields
    private int number;
}


import javax.swing.JOptionPane;

public class MyIntNumberTestt
{
    public static void main(String[] args)
    {
        int number, num;

        String input = JOptionPane.showInputDialog("enter a value to cube and gather  the sum of");
        num = Integer.parseInt(input);

        MyIntNumberr richard = new MyIntNumberr(num);

        richard.calcCubeAndSum(num);

        System.exit(0);
    }
}

Answer 1

我没有在您的代码中看到您累积立方体总和的位置...

static Scanner input = new Scanner(System.in);

public static void main(String[] args) throws Exception {    
    System.out.print("Enter a value to cube and gather the sum of: ");
    int num = input.nextInt();
    calcCubeAndSum(num);
}

private static void calcCubeAndSum(int num) {
    if (1 <= num && num <= 20) {
        int sum = 0;
        while (num <= 20) {
            // Calculate the cube
            int cube = num * num * num;

            // Accumulate the cube into a sum
            sum += cube;

            // Display current result
            System.out.println("Current number: " + num + "\tCubed: " + cube + "\tCurrent Sum: " + sum);

            // Go to the next number
            num++;
        }
        // Display Total Sum
        System.out.println("Total Sum: " + sum);
    } else {
        System.out.println("That integer is invalid please try again");
    }
}

结果：

Answer 2

这是使用 Python 查找 N 个自然数的简单方法 希望大家喜欢....

n = int(input("Enter the value of n:"))
for i in range (1,n+1):
    print(i)

回答

Enter the value of n:10
1
2
3
4
5
6
7
8
9
10