为什么此代码为相同的输入提供两个不同的输出？

Question

对于输入（12134），在某些情况下它给出输出：“是”，在某些情况下它给出“否”。

package nagarroBootcamp;

import java.util.Scanner;

public class OddEven {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        int carnum = 0;
        int lastDigit = 0;
        int sumOfEven = 0;
        int sumOfOdd = 0;
        for (int i = 1; i <= N; i++) {
            carnum = sc.nextInt();
            int temp = carnum;
            while (temp > 0) {
                lastDigit = temp % 10;
                if (lastDigit % 2 == 0) {
                    sumOfEven += lastDigit;
                } else {
                    sumOfOdd += lastDigit;
                }
                temp /= 10;
            }

            if (sumOfEven % 4 == 0 || sumOfOdd % 3 == 0)
                System.out.println("Yes");
            else
                System.out.println("No");

        }

    }

}

Answer 1

原因是，您没有为后续输入重置这些变量，您只是在开始时将它们初始化一次，所以只有第一个结果实际上是相关的

public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        for (int i = 1; i <= N; i++) {
            int carnum = 0;
            int lastDigit = 0;
            int sumOfEven = 0;
            int sumOfOdd = 0;
            carnum = sc.nextInt();
            int temp = carnum;
            while (temp > 0) {
                lastDigit = temp % 10;
                if (lastDigit % 2 == 0) {
                    sumOfEven += lastDigit;
                } else {
                    sumOfOdd += lastDigit;
                }
                temp /= 10;
            }

            if (sumOfEven % 4 == 0 || sumOfOdd % 3 == 0) {
                System.out.println("Yes");
            } else {
                System.out.println("No");
            }
        }

    }