【发布时间】:2022-01-11 08:13:41
【问题描述】:
我在左侧显示菜单。到目前为止,菜单没有问题。
现在我正在处理后退按钮。一旦用户点击Demo1 -> Demo 1.1 然后它将显示Demo 1.1.1, Demo 1.1.2 等。所以我打算在顶部显示返回按钮
//back
Demo1->Demo 1.1
//dropdown
Demo 1.1.1
Demo 1.1.2
Demo 1.1.3
Demo 1.1.4
注意:我的菜单是完全动态的,我不想添加静态值。
$('.menu-item-has-children .sub-menu').css({
'left': '-320px'
});
$('.menu-item-has-children > a').click(function() {
//alert('hello');
var positionMenu = $(this).parent().attr('id');
//console.log(positionMenu);
$('.menu-item-has-children[id=' + positionMenu + '] > .sub-menu').css({
'left': '0px'
});
var pMenu1 = $(this).text();
console.log(pMenu1);
$('.secondary').prepend(pMenu1);
});
ul {
padding-left: 0;
}
.secondary {
z-index: 99;
background: #f8f8f8;
-webkit-box-shadow: 0 8px 24px rgba(229, 228, 230, 0.4);
box-shadow: 0 8px 24px rgba(229, 228, 230, 0.4);
-webkit-transition: left 0.2s ease, width 0.2s ease;
transition: left 0.2s ease, width 0.2s ease;
border-right: 1px solid #eaedf1;
position: fixed;
top: 0;
height: 100%;
padding: 12px;
width: 320px;
}
.menu li {
padding-bottom: 10px;
padding-left: 23px;
list-style: none;
}
.menu-item-has-children>a {
position: relative;
display: block;
}
.menu-item-has-children .sub-menu {
width: 100%;
height: 100%;
padding-top: 40px;
background: #f8f8f8;
list-style: none;
position: absolute;
top: 0;
left: 0;
transition: left .3s;
z-index: 10;
}
.menu-item-has-children>a::after {
display: inline-block;
vertical-align: middle;
font-family: "Font Awesome 5 Free";
font-weight: 900;
content: "\f054";
position: absolute;
right: 05px;
top: 0px;
font-size: 12px;
}
<script src="https://kit.fontawesome.com/97446b8f60.js" crossorigin="anonymous"></script>
<div class="secondary">
<ul id="menu-inner-page-menu" class="menu">
<li>Home</li>
<li id="menu-item-204" class="menu-item-has-children"><a href="#">Demo1</a>
<ul class="sub-menu">
<li id="menu-item-304" class="menu-item-has-children"><a href="#">Demo 1.1</a>
<ul class="sub-menu">
<li><a href="">Demo 1.1.1</a></li>
<li><a href="">Demo 1.1.2</a></li>
<li><a href="">Demo 1.1.2</a></li>
</ul>
</li>
<li id="menu-item-305"><a href="">Demo 1.2</a></li>
<li id="menu-item-306"><a href="">Demo 1.3</a></li>
<li id="menu-item-307"><a href="">Demo 1.4</a></li>
</ul>
</li>
<li id="menu-item-205" class="menu-item-has-children"><a href="#">Demo2</a>
<ul class="sub-menu">
<li id="menu-item-315"><a href="">Demo 2.1</a></li>
<li id="menu-item-316"><a href="">Demo 2.2</a></li>
</ul>
</li>
</ul>
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
现在我正在控制台中获取输出。
同样获取 HTML 视图源代码
现在,如何使可点击?
【问题讨论】:
标签: javascript html jquery css nav