不知道如何将英语转换为拉丁猪 java 代码

Question

这是我编写此代码的尝试，但我迷失了主要部分。我不确定循环如何知道新单词何时开始。现在我只知道循环和 if-else 语句。我如果您能将我推向正确的方向，我将不胜感激，因为这个问题对我来说太难了。

猪拉丁语规则： 1）如果单词以元音开头，则在末尾添加破折号和“方式”。 2）否则，添加破折号，将第一个字母移到末尾，并添加“ay”

/*Enter a line of text: This is a test.

  Input: this is a test.
  Output: his-tay is-way a-way est-tay.
*/



import java.util.Scanner;
public class PigLatin
{
    public static void main(String[]args)
    {
       int count;
       String input;
       char empty = ' ',first;

       Scanner keyboard = new Scanner(System.in);
       System.out.print("Enter a line of text: ");
       input = keyboard.nextLine();
       System.out.println(); 

       for(count = 0; count < input.length(); count++)
            if(input.charAt(0) != 'a' || input.charAt(0) != 'e' != input.charAt(0) != 'o' != input.charAt(0) != 'i' != input.charAt(0) != 'u')
                System.out.print(input.charAt(count + 1) + "-" + input.charAt(0) + "ay");
            else if(input.charAt(count) == empty) 
                    first = input.charAt(count + 1)
                    if(input.charAt(first) != 'a' || input.charAt(0) != 'e' != input.charAt(0) != 'o' != input.charAt(0) != 'i' != input.charAt(0) != 'u')
                    System.out.print(input.charAt(first + 1) + "-" + input.charAt(first) + "ay");
            else if()
                    System.out.print("-way"); //I'm lost here.
     }
 }

Answer 1

尝试以下方法：

import java.util.Scanner;
public class PigLatin {

    static final char vowelRegex = "^[aeiouy]"; //Is y a vowel?

    public static void main(String[]args) {
        Scanner keyboard = new Scanner(System.in);
        System.out.print("Enter a line of text: ");
        String input = keyboard.nextLine();
        String[] words = input.split(' ');

        for(int i=0; i<words.length; i++) {
            if(words[i].matches(vowelRegex)) {
                System.out.print(words[i] + "-way ");
            } else {
                System.out.println(words[i].substring(1) + words[i].charAt(0) + "-ay ";
            }
        }
    }
}