python比较文本文件 - 如果其他打印

Question

我有 4 个以下格式的文本文件

keycountry.txt

UK USA Germany

国家/地区.txt

Brexit - UK
USA UK Relations
France win world cup

keylink.txt

www.abc.com
www.ddd.com
www.eee.com

链接.txt

www.abc.com
www.eee.com

代码：

import re

keycountryfile = "keycountry.txt"
countryfile = "country.txt"

links = open('links.txt', 'r')
links_data = links.read()
links.close()

keys = open('keylink.txt', 'r')
keys_data = keys.read()
keys.close()

keys_split = keys_data.splitlines()

print('LINKS')
for url in keys_split:
    if url in links_data:
        print(url)
        print("matching")
else:
    print("Not matching")   

keys = set(key.lower() for key in 
    re.findall(r'\w+', open(keycountryfile , "r").readline()))

print("COUNTRY")
with open(countryfile) as f:
    for line in f:
        words = set(word.lower() for word in re.findall(r'\w+', line))
        if keys & words:
            print(line, end='')
            print("matching")
    else:
        print("Not matching")

在代码中print("matching") 重复了多次。我知道，因为它在循环内，所以它会重复，print("Not matching") 在没有匹配项时不会显示。我尝试将打印语句放在循环内部和外部，但我无法解决问题。

如果匹配，输出应该是这样的：

LINKS
www.abc.com
www.eee.com
matching

COUNTRY
Brexit-UK
USA UK Relations
matching

如果不匹配，输出应该是这样的：

LINKS
Not matching
COUNTRY
Not matching

如何解决这个问题？

Answer 1

似乎您的问题一方面与 for-else 构造有关。否则将始终在您的代码中执行。

此外，基于 kaihami 的回答，要实现您所描述的内容，您需要将匹配的链接/行存储在一个单独的结构中，如列表，然后检查该列表是否为空以打印匹配的条目或字符串“Not匹配”，这是我提出的解决方案：

import re

keycountryfile = "keycountry.txt"
countryfile = "country.txt"

with open('links.txt', 'r') as links:
    links_data = [line.strip() for line in links.readlines()]

with open('keylink.txt', 'r') as keys:
    keys_links = set([line.strip() for line in keys.readlines()])


matching_links = []
for url in links_data:
    if url in keys_links:
        matching_links.append(url)

print('LINKS')
if matching_links:
    print('\n'.join(matching_links))
    print("matching")
else:
    print("Not matching") 

print()

with open(keycountryfile , "r") as f:
    country_keys = set(key.lower() for key in 
                       re.findall(r'\w+', f.readline()))

matching_lines = []
with open(countryfile) as f:
    for line in f:
        words = set(word.lower() for word in re.findall(r'\w+', line))
        if country_keys & words:
            matching_lines.append(line.strip())
    print("COUNTRY")
    if matching_lines:
        print('\n'.join(matching_lines))
        print("matching")
    else:            
        print("Not matching")

Answer 2

您可以将结果保存到列表中，并在找到所有匹配项后打印结果。

import re

keycountryfile = '''UK USA Germany'''
countryfile = '''Brexit - UK
USA UK Relations
France win world cup'''

links = '''www.abc.com
www.eee.com'''

links_data = links.split()

keys = '''www.abc.com
www.ddd.com
www.eee.com'''
keys_data = keys.split()


keys_split = keys_data

matching_links = []
not_links = []
for url in keys_split:
    if url in links_data:
        matching_links.append(url)
    else:
        not_links.append(url)

keys = set(keycountryfile.split())

matching_country = []
not_country = []
for line in countryfile.split():
    words = set(word.lower() for word in re.findall(r'\w+', line))
    if keys & words:
        matching_country.append(line)
    else:
        not_country.append(line)

print('LINKS')
if matching_links:
    print('\n'.join(matching_links))
    print("matching")

print("COUNTRY")
print()
if matching_country:
    print('\n'.join(matching_country))
    print("matching")

print('LINKS')
if not_links:
    print('\n'.join(not_links))
print("Not matching")

print("COUNTRY")
if not_country:
    print('\n'.join(not_country))
print("Not matching")

你可以试试这个代码here