如何扫描循环内的行并将其插入 ArrayList？ [复制]

Question

我正在创建一个包含用户在控制台中输入的字符串的数组列表。问题是当他们输入超过 2 个单词的 String 时，程序无法按预期运行。

这是我目前所拥有的：

  ArrayList<String> list = new ArrayList<String>();      
  Scanner scan = new Scanner (System.in);      
  int i;

  System.out.print("How many TV shows do you hope to watch this week? ");
  i = scan.nextInt(); 
  scan.nextLine();

  for(int j = 0; j<i; j++){
     System.out.print("Enter show " + (j+1) + ": ");
     list.add(scan.nextLine());
  }

  System.out.print("Have you caught up to any shows (answer yes or no): ");

   while (scan.nextLine().equalsIgnoreCase("yes")){
     System.out.print("Which show? ");
     String show = new String(scan.nextLine());
     if(list.contains(show)){
        list.remove(list.indexOf(show));
     }else { 
        System.out.print("That show is not on original list!");
     }
  }


  System.out.println("Here's what you still have to watch this week:");
  System.out.println(list);        

顺便说一句，我已经尝试从 next() 更改为 nextLine() 它仍然无法按预期工作。

我的预期输出如下：

示例 1：假设您没有赶上任何节目 （这工作，感谢用户的回应，在下面）

 How many TV shows do you hope to watch this week? 3
 Enter show 1: RWBY
 Enter show 2: Kengan Ashura
 Enter show 3: The Good Place
 Have you caught up to any shows (answer yes or no): no
 Here's what you still have to watch this week:
 [RWBY, Kengan Ashura, The Good Place]

示例 2：假设您已经赶上了一个节目并将更新列表 （不工作）

 How many TV shows do you hope to watch this week? 3
 Enter show 1: Father Brown
 Enter show 2: Death in Paradise
 Enter show 3: Watchmen
 Have you caught up to any shows (answer yes or no): yes
 Which show? Death in Paradise
 Any other shows you're caught up with? (yes/no) no
 Here's what you still have to watch this week:
 [Father Brown, Watchmen]

示例 3：假设您赶上了一个节目，但它不在列表中。 （它不会更新列表，因为将您赶上的新节目添加到列表中只是为了删除它是没有意义的。）

 How many TV shows do you hope to watch this week? 2
 Enter show 1: Watchmen
 Enter show 2: RWBY
 Have you caught up to any shows (answer yes or no): yes
 Which show? Monday Night Football
 That show is not on original list!
 Any other shows you're caught up with? (yes/no) no
 Here's what you still have to watch this week:
 [Watchmen, RWBY]

谢谢！

Answer 1

我是这样得到你可能需要的东西的：

    Set<String> list = new HashSet<>();
    Scanner scan = new Scanner (System.in);

    System.out.print("How many TV shows do you hope to watch this week? ");
    int i = Integer.parseInt(scan.nextLine());

    for(int j = 0; j<i; j++){
        System.out.print("Enter show " + (j+1) + ": ");

        list.add(scan.nextLine());
    }

    System.out.print("Have you caught up to any shows (answer yes or no): ");

    String showName;
    String answer;
    do {
        answer = scan.nextLine();
        if (answer.equalsIgnoreCase("no")) {
            break;
        } else {
            System.out.print("Which show? ");

            showName = scan.nextLine();
            if(list.contains(showName)){
                list.remove(showName);
            } else {
                System.out.println("That show is not on original list!");
            }

            System.out.println("Any other shows you're caught up with? (yes/no): "); // What yo do if I don't 
            // enter a "yes" or a "no"?
        }
    } while(answer.equalsIgnoreCase("yes"));

    System.out.println("Here's what you still have to watch this week:");
    System.out.println(list);

1. 首先，我建议您使用Set<String> 而不是List<String>，就像我在代码中所做的那样。
2. 其次，想想用户可以在哪些地方输入不应该输入的值，以及如何处理它们。比如，当你想输入观看的节目数量时，如果我输入一个单词，就会抛出异常，如何处理？如果我输入“是”或“否”以外的任何内容，如何处理这种情况？

Answer 2

我没有发现用户输入多个字符串的问题。 这是我所拥有的：

          ArrayList<String> list = new ArrayList<String>();      
          Scanner scan = new Scanner (System.in);      
          int i; String in;

          System.out.print("How many TV shows do you hope to watch this week? ");
          i = scan.nextInt(); 
          scan.nextLine();

          for(int j = 0; j<i; j++){
             System.out.print("Enter show " + (j+1) + ": ");
             list.add(scan.nextLine());
          }


          System.out.print("Have you caught up to any shows (answer yes or no): ");
          in = scan.nextLine(); 

          if(in.equalsIgnoreCase("yes")) {
              boolean more = true;

              while(more) {
                  System.out.print("Which show? ");
                  String show = new String(scan.nextLine());
                  if(list.contains(show)){
                     list.remove(list.indexOf(show));
                  }else { 
                     System.out.println("That show is not on original list!");
                  }
                  System.out.print("Any other shows you're caught up with? (yes/no): ");
                  in = scan.nextLine(); 
                  if(!in.equalsIgnoreCase("yes")) {
                      more = false;
                  }
              }

          }

          System.out.println("Here's what you still have to watch this week:");
          System.out.println(list);

我使用了一个 while 循环来检测用户是否有更多他们关注的节目。