如何避免两次输入值

Question

描述：假设我们可以从自动售货机上以每块 1 美元的价格购买一块巧克力棒。每个巧克力里面 酒吧是优惠券。我们可以从机器上用六张优惠券兑换一根巧克力棒。这表示 一旦你开始从机器上购买巧克力棒，你总会有一些优惠券。

编写一个程序来知道如果我们从 N 美元开始并且总是可以吃多少巧克力棒 如果我们有足够的额外巧克力棒，请兑换优惠券。

我需要编写两个函数并使用for循环。

我不想输入两次美元值。

#include <iostream>
using namespace std;

int chocCalc(int n){

    int choc = 0, coup = 0, moreChoc = 0, dollars;

    cout << "Enter dollars: ";
    cin >> dollars;

// Calculating for amount of chocolates including the ones reedemed by cupons.


    int i=0;
    for (i = 1; i <= dollars; i++  ){
    choc = dollars;
    coup = choc;
    moreChoc = coup / 6;
    choc += moreChoc;

    return choc;
    }

}

int cupon(int m){

    int choc = 0, coup = 0, moreChoc = 0, dollars, coupLeft = 0;

    cout << "Enter dollars again: ";
    cin >> dollars;


    int i=0;
    for (i = 1; i <= dollars; i++  ){
    choc = dollars;
    coup = choc;

// calculating the amount of cupons left


    moreChoc = coup / 6;
    choc += moreChoc;
    coupLeft = coup%6;

    return coupLeft;
    }

}
int main(){

    cout << "You can eat: " << chocCalc(0) << " chocolates \n";
    cout << "and " << cupon(0) << " cupons are left.";


    return 0;
}

Answer 1

没有全局变量

#include <iostream>

using namespace std;

int enterDollars(){
     int dollars;
     cout<<"Enter Dollars:";
     cin>>dollars;
     return dollars;
}
int chocCalc(int dollars){

    int choc = 0, coup = 0, moreChoc = 0;


// Calculating for amount of chocolates including the ones reedemed by cupons.


    int i=0;
    for (i = 1; i <= dollars; i++  ){
    choc = dollars;
    coup = choc;
    moreChoc = coup / 6;
    choc += moreChoc;

    return choc;
    }

}

int cupon(int dollars){

    int choc = 0, coup = 0, moreChoc = 0, coupLeft = 0;




    int i=0;
    for (i = 1; i <= dollars; i++  ){
    choc = dollars;
    coup = choc;

// calculating the amount of cupons left


    moreChoc = coup / 6;
    choc += moreChoc;
    coupLeft = coup%6;

    return coupLeft;
    }

}
int main(){
    int dollars = enterDollars();
    cout << "You can eat: " << chocCalc(dollars) << " chocolates \n";
    cout << "and " << cupon(dollars) << " cupons are left.";


    return 0;
}