动态生成的 Mocha 测试不在异步/等待上下文中执行

Question

我无法让我的 Mocha 测试运行。我需要测试的部分内容是我以异步方式（从远程服务器）获取的，由我的getStatus() 函数返回（为简单起见，由超时替换）。我有一个没有 async/await 的类似代码示例，它工作正常（如果需要也可以提供 repl.it）。

简化代码（你可以玩here on repl.it）：

const sleep = require('util').promisify(setTimeout);

const getStatus = async function() {
    await sleep(1000);
    return 2;
};

describe('main describe', async function () {
    let uids = [1,2,3];

    describe('Tha test!', async function () {
        console.info('started describe() block...');

        let outcome;
        let status;

        const callback = function () {
            console.info(`inside callback, status is ${status} and outcome is ${outcome}`);
            expect(status).to.equal(outcome);
        };

        for(let uid in uids) {
            status = await getStatus(uids[uid]);
            console.info('the status returned by getStatus is:', status);
            it(`The status for ${uids[uid]} should be ${outcome}`, callback);
        }
    });
});

注意：it() 子句中的回调是受this question 启发的。

输出：

started describe() block...

  0 passing (0ms)

the status returned by getStatus is: 2
the status returned by getStatus is: 2
the status returned by getStatus is: 2

预期输出：

started describe() block...

the status returned by getStatus is: 2
the status returned by getStatus is: 2
the status returned by getStatus is: 2

      1) number 0 should equal 2
      2) number 1 should equal 2
      ✓ number 2 should equal 2

  1 passing (11ms)
  2 failing

问题：为什么我的it() 子句没有执行？

Answer 1

原来你不能将async 回调传递给describe()。谁知道呢。

所以为了让所有异步工作正常工作，应该这样做：

describe('do not put async before the function keyword!', function () {
    uids = process.env.ENV_OBJECTS.split(',');

    let outcome;

    for(let uid in uids) {
        it('Can safely put async before the function here', async function() {
            outcome = await getOutcome(uid);
            // etc.
        });
    }
});